Answer:

Step-by-step explanation:
Hello,
a and b are the zeros, we can say that

So we can say that

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b
for instance we can write

and we can notice that
so
![(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab](https://tex.z-dn.net/?f=%28x-2a-3b%29%28x-3a-2b%29%3Dx%5E2-5%28a%2Bb%29x%2B6%5B%28a%2Bb%292-2ab%5D%2B13ab%5C%5C%3D%20x%5E2-5%28a%2Bb%29x%2B6%28a%2Bb%29%5E2%2Bab)
it comes

multiply by 3

Answer: 1
Step-by-step explanation:
All you had to do was multiply g by 1 so f(g(1)) as a value is 1
Answer:
1. a
2. 
Step-by-step explanation:
1. Since there is one value of y for every value of x in (−1,0),(−4,5),(3,2),(−3,5), this relation is a function.
2. To find the inverse, interchange the variables and solve for y.

10+3x Or 3x+10.
This is because he gets 10 dollars add it to the 3 he gets per dog. The per dog is X as you don’t know how many dogs he gets
It is B:23 centimeters 54+56=110. 63+70=133 133-110= 23c