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1 year ago

Write an equation in slope-intercept form for each graph shown

Mathematics

1 answer:

AveGali [126]1 year ago

7 0

Answer:
1). Y=4x-2
2). Y= 2x-1

Explanation:
For the first graph
Slope = 4
Y intercept = -2
Y=mx+b
Y= 4x-2
For the second graph
Slope = 2
Y intercept =-1
Y=mx+b
y= 2x-1

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5 ft

Effectus [21]

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2 years ago

Someone please help me

Lerok [7]

Answer:

y=3x+5

Step-by-step explanation:

I think that this is what they mean...

y=mx+b

y=3x+b

y=3x+5

plug in #s

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3 years ago

Any volunteer please help

den301095 [7]

Answer:

Part A)

The equation in the point-slope form is:

$y-11=\frac{4}{3}\left(x-\left(-2\right)\right)$

Part B)

The graph of the equation is attached below.

Step-by-step explanation:

Part A)

Given

The point = (-2, 11)

m = 4/3

The point-slope form of the line equation is

$y-y_1=m\left(x-x_1\right)$

Here, m is the slope and (x₁, y₁) is the point

substituting the values m = 4/3 and the point (-2, 11) in the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

$y-11=\frac{4}{3}\left(x-\left(-2\right)\right)$

Thus, the equation in the point-slope form is:

$y-11=\frac{4}{3}\left(x-\left(-2\right)\right)$

Part B)

As we have determined the point-slope form which passes through the point (-2, 11) and has a slope m = 4/3

The graph of the equation is attached below.

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2 years ago

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Andreyy89

I think it is 6 ways

idk for sure tho

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3 years ago