All categories

3 years ago

Need help on how to cancel out denominators if they're different, please explain thoroughly, thanks!

Mathematics

2 answers:

ElenaW [278]3 years ago

5 0

You can make a common denominator, then multiple the top by said denominator, then cross it out - because they are the same

Sergeeva-Olga [200]3 years ago

4 0

Answer:

x = 2 12/13

Step-by-step explanation:

(x - 4)/7 = (8 - 3x)/5

A fraction is the same as a division problem, and you can see that x-4 is being divide by 7

The opposite of dividing by 7 is multiplying by 7

Multiply both sides by 7

x-4 = (8-3x)/5 * 7

x - 4 = 56 - 21x/5

Now multiply both sides by 5

5x - 20 = 56 - 21x

Now solve:

5x - 20 = -21x + 56

26x - 20 = 56

26x = 76

x = 2 12/13

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

You might be interested in

How effective is the regression model for these data? not effective, because only 13.4% of the variation in the data is explaine

Elden [556K]

Answer:45

Step-by-step explanation:

3 0

3 years ago

A tourist group arrived at the boat dock for a boat ride in the morning. There were 252 people in the group. Another tourist gro

seraphim [82]

Okay, so to get the answer we have to divide.

252(morning group) divided by 36 = 7 trips

288(afternoon group) divided by 36= 8 trips

7 + 8 =
Answer: 15trips

8 0

4 years ago

round off to the nearest thousand ( 3 decimal places) a, 534.9799= b, 2.67905= c,88.61124= d, 705.1487= e,7905.4321= f,3 7705= p

Amiraneli [1.4K]

Answer:

A.535 B.3 C.88.611 D.705.2

Step-by-step explanation:

You round all the way down

5 0

3 years ago

I need help!!!! a b c or d

sleet_krkn [62]

Answer:

-3

Step-by-step explanation:

it is right

7 0

3 years ago

Two buildings on opposites sides of a highway are 3x^3- x^2 + 7x +100 feet apart. One building is 2x^2 + 7x feet from the highwa

iVinArrow [24]

Given:

Distance between two buildings = $3x^3- x^2 + 7x +100$ feet apart.

Distance between highway and one building = $2x^2 + 7x$ feet.

Distance between highway and second building = $x^3 + 2x^2 - 18$ feet.

To find:

The standard form of the polynomial representing the width of the highway between the two building.

Solution:

We know that,

Width of the highway = Distance between two buildings - Distance of both buildings from highway.

Using the above formula, we get the polynomial for width (W) of the highway.

$W=3x^3- x^2 + 7x +100-(2x^2 + 7x)-(x^3 + 2x^2 - 18)$

$W=3x^3- x^2 + 7x +100-2x^2-7x-x^3 -2x^2+18$

Combining like terms, we get

$W=(3x^3-x^3)+(- x^2 -2x^2-2x^2)+ (7x -7x)+(100 +18)$

$W=2x^3-5x^2+0+118$

$W=2x^3-5x^2+118$

Therefore, the width point highway is $2x^3-5x^2+118$ .

8 0

3 years ago