Consider an equation of a circle given (x-3)² + (y+7)² = 4 What is the center of the circle?
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Answer:
Step-by-step explanation:
The question is incomplete. Here is the complete question.
The upper-left coordinates on a rectangle are (−5,6) and the upper-right coordinates are (−2,6). The rectangle has a perimeter of 16units. Draw the rectangle on the coordinate plane below.
If the coordinates of the top of the triangle (breadth) is (−5,6) and (−2,6), we can calculate the breadth of the rectangle by taking the difference between the two points using the formula:
D = √(y₂-y₁)²+(x₂-x₁)²
Given x₁ = -5, y₁= 6, x₂ = -2 and y₂ = 6
D = √(6-6)²+(-2-(-5))²
D = √0²+3²
D = √9
D = 3 units
Breadth = 3 units
Given the Perimeter to be 16 units and the formula for calculating the perimeter of rectangle t be P = 2(L+B), we can get the length of the rectangle.
16 = 2(3+L)
16 = 6+2L
16-6 = 2L
2L = 10
L = 10/2
L = 5 units.
<em>Hence the length of the rectangle is 5 units and the breadth is 3 units. Find the diagram in the attachment.</em>
