Question:
Solution:
Let the following equation:
![\sqrt[]{12-x}=\text{ x}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B12-x%7D%3D%5Ctext%7B%20x%7D)
this is equivalent to:
![(\sqrt[]{12-x})^2=x^2](https://tex.z-dn.net/?f=%28%5Csqrt%5B%5D%7B12-x%7D%29%5E2%3Dx%5E2)
this is equivalent to:

this is equivalent to:

thus, we can conclude that
x= 3.
Answer:
The volume of the figure is ![(\frac{l^{3}}{3})[\frac{\pi }{2}-1]\ units^{3}](https://tex.z-dn.net/?f=%28%5Cfrac%7Bl%5E%7B3%7D%7D%7B3%7D%29%5B%5Cfrac%7B%5Cpi%20%7D%7B2%7D-1%5D%5C%20units%5E%7B3%7D)
Step-by-step explanation:
we know that
The volume of the figure is equal to the volume of the cone minus the volume of the square pyramid
step 1
Find the volume of the cone
The volume of the cone is equal to

we have
----> the diagonal of the square base of pyramid is equal to the diameter of the cone

substitute

step 2
Find the volume of the square pyramid
The volume of the pyramid is equal to

where
B is the area of the base
h is the height of the pyramid
we have


substitute


step 3
Find the volume of the figure
![\frac{1}{6}\pi (l)^{3}\ units^{3}-\frac{1}{3}l^{3}\ units^{3}=(\frac{l^{3}}{3})[\frac{\pi }{2}-1]\ units^{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%7D%5Cpi%20%28l%29%5E%7B3%7D%5C%20units%5E%7B3%7D-%5Cfrac%7B1%7D%7B3%7Dl%5E%7B3%7D%5C%20units%5E%7B3%7D%3D%28%5Cfrac%7Bl%5E%7B3%7D%7D%7B3%7D%29%5B%5Cfrac%7B%5Cpi%20%7D%7B2%7D-1%5D%5C%20units%5E%7B3%7D)
Answer:
y = x + 3
Step-by-step explanation:
This is because the number is increasing by three each time and if you substituted the variable x with a number the answer is true.
The answer would be 0.15 because in a deck there are only 4 cards of 8 (diamonds, hearts, clovers, and spades). Since there are 52 cards, you would divide 8 by 52 to get 0.153846, but since it says to round to the nearest hundredths, the answer would be 0.15.
Answer:
9.407x10-11
Step-by-step explanation:
8.18(9.407x(10)−11)10−6(1.15(9.407x(10)−11)10−5)
8.18(9.407x(10)−11)10−6(1.15(9.407x(10)−11)10−5)