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3 years ago

The sum of two consecutive numbers is 31. Let x = the smaller number. Which let statement would you use for the larger number?

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

7 0

Answer:

Let (x+1) = the larger number

Step-by-step explanation:

Two consecutive numbers differ by 1. The larger is 1 more than the smaller. The expression for 1 more than x is (x+1).

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The width of a rectangular room is 80%

katrin [286]

Answer:

12 feet

Step-by-step explanation:

Given: length = 15 feet, width = L x 80%

Unknown: width = ?

width = L x 80%

w = (15ft) x 80% or (15ft) x .80

w = 12 ft

5 0

3 years ago

Read 2 more answers

A cell phone plan costs $200 to start. Then there is a $50 charge each month. Is there a proportional relationship between time

xxMikexx [17]

Answer:

Step-by-step explanation:

The equation is

y = 200+50x

This is not a proportional relationship because it does not go through the origin

If x=0, y does not equal 0

8 0

3 years ago

Which table shows a proportional relationship between x and y? A. x y 2 4 3 6 4 9 B. x y 3 4 9 16 15 20 C. x y 4 12 5 15 6 18 D.

Sliva [168]

Answer:

Step-by-step explanation:

The relationship is proportion if y/x is constant.

So it is C because 12/4 = 15/5 = 18/6 = 3.

7 0

3 years ago

Point: (-3, 7); Slope: 4

GaryK [48]

Answer:

y - 7 = 4(x + 3)

Step-by-step explanation:

Write the equation of a line using the point slope formula. Substitute m = 4 and the point (-3,7) in the formula.

$y - y_1 = m(x-x_1)\\y - 7 = 4(x--3)\\y - 7 = 4(x+3)$

6 0

3 years ago

Find the area of the shaded region

o-na [289]

so hmmm let's get the area of the whole hexagon, and then get the area of the circle inside it, then <u>subtract the area of the circle from that of the hexagon's</u>, what's leftover is what we didn't subtract, namely the shaded part.

$\textit{area of a regular polygon}\\\\ A=\cfrac{1}{4}ns^2\cot\stackrel{\stackrel{degrees}{\downarrow }}{\left( \frac{180}{n} \right)}~ \begin{cases} n=\textit{number of sides}\\ s=\textit{length of a side}\\[-0.5em] \hrulefill\\ n=\stackrel{hexagon}{6}\\ s=\frac{9}{2} \end{cases}\implies A=\cfrac{1}{4}(6)\left( \cfrac{9}{2} \right)^2 \cot\left( \cfrac{180}{6} \right)$

$A=\cfrac{1}{4}(6)\cfrac{9^2}{2^2} \cot(30^o)\implies A=\cfrac{243}{8}\cot(30^o)\implies A=\cfrac{243\sqrt{3}}{8} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=\frac{4}{5} \end{cases}\implies A=\pi \left( \cfrac{4}{5} \right)^2\implies A=\cfrac{16\pi }{25} \\\\[-0.35em] ~\dotfill$

$\stackrel{\textit{area of the hexagon}}{\cfrac{243\sqrt{3}}{8}}~~ - ~~\stackrel{\textit{area of the circle}}{\cfrac{16\pi }{25}}\implies \cfrac{6075\sqrt{3}-128\pi }{200}$

5 0

2 years ago