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Leni [432]
3 years ago
5

The sum of two consecutive numbers is 31. Let x = the smaller number. Which let statement would you use for the larger number?

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
7 0

Answer:

  Let (x+1) = the larger number

Step-by-step explanation:

Two consecutive numbers differ by 1. The larger is 1 more than the smaller. The expression for 1 more than x is (x+1).

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2 What is the range of the numbers 11, 24, 37, 44, and 62? 24.44 11372 A6 A А 62 B. 52 С 51 D 49​
inessss [21]

Answer:

range = 51

Step-by-step explanation:

Range = biggest - smallest

62 - 11 = 51

5 0
3 years ago
Calculate the length of AC to one decimal place in the trapezium below.
a_sh-v [17]

Answer:

First we will split trapezium on two geometric figure.

One is rectangle and the second is right triangle.

When we subtract 11-4=7cm  we get one cathetus of the right triangle a=7cm also we know hypotenuse which is c=16cm.

We will use Pythagorean theorem to find the second cathetus b

b=√16∧2-7∧2= √256-49= √207 ≈ 14.39cm =DC =>

AC =√(DC)∧2+(AD)∧2= √14.39∧2+11∧2= √207+121= √328= 18.1cm

AC=18.1cm

Good luck!!

7 0
3 years ago
Eight more than three times the difference of four and a number” when n = 3?
Snezhnost [94]
8 + 3 (4 - n )
n= 3 
8 + 3( 4-3)
8 + 3 * 1 
8 + 3 = 11
8 0
3 years ago
The scale of the map is messing the actual distance from library to the west quill is 72 miles and it is 6 inches on the map wha
Sonbull [250]

Answer:

A) 12 miles per inch

B) 36 miles from west quail, 48 from liberty

5 0
2 years ago
Prove this trigonometric equation;<br><br> - tan^2x + sec^2x = 1,
alekssr [168]
Hey there :)

- tan²x + sec²x = 1    or    1 + tan²x = sec²x

sin²x + cos²x = 1 
Divide the whole by cos²x

\frac{sin^2x}{cos^2x} + \frac{cos^2x}{cos^2x} = \frac{1}{cos^2x}

\frac{sinx}{cosx} = tanx so \frac{sin^2x}{cos^2x} = tan^2x
and
\frac{1}{cosx} = secx so \frac{1}{cos^2x} = sec^2x

Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}

1 = - tan²x = sec²x or sec²x - tanx = 1

3 0
3 years ago
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