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3 years ago

Write the conversion factor for converting meters to centimeters.

Mathematics

2 answers:

Alchen [17]3 years ago

7 0

Answer:100cm/1m

Step-by-step explanation:

Dafna1 [17]3 years ago

3 0

Hello!

There are 100 centimeters in a meter

So the answer is A

Hope this helps!

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James deposited $575 into a bank account that earned 5.5% simple interest each year. If no money was deposited into or withdrawn

Usimov [2.4K]

I=prt,,i=575*0.055*2,,i=63.25 total interest then A=p+i,,a=575+63.25,,A=638.25 the answer

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3 years ago

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If a triangle has sides of 14,48, and 50 units respectively what type of triangle is it

Lunna [17]

Answer:

it is scalene type of triangle because no sides are equal

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2 years ago

Someone help please!!!

Bad White [126]

Answer:

A. P - Q

Step-by-step explanation:

Q(x) = (x³ + 2x² + 3)(x² -2)

= x⁵ - 2x³ + 2x⁴ - 4x² + 3x² - 6

P - Q = (x⁵ - 2x³ + 2x⁴ - 4x² + 3x² - 6) - (x⁴ + 3x³ + 2x² - x + 2)

P - Q = x⁵ - x⁴ + 2x⁴ - 3x³ - 2x³ - 2x² - 4x² + 3x² + x - 2 - 6

P - Q = x⁵ + x⁴ - 5x³ - 3x² + x - 8

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2 years ago

a cookie jar contains four oatmeal raisin, one sugar, nine chocolate chip, and six peanut butter cookies. if one is chosen at ra

VikaD [51]

Step-by-step explanation:

There are a total of 4 + 1 + 9 + 6 = 20 cookies. So the probabilities of each type for a random cookie are:

P(oatmeal raisin) = 4/20 = 1/5

P(sugar) = 1/20

P(chocolate chip) = 9/20

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2 years ago

A random survey of 1000 students nationwide showed a mean ACT score of 21.1. Ohio was not used. A survey of 500 randomly selecte

vodka [1.7K]

Answer:

We conclude that the mean Ohio score is below the national average.

Step-by-step explanation:

We are given that a random survey of 1000 students nationwide showed a mean ACT score of 21.1. Ohio was not used.

A survey of 500 randomly selected Ohio scores showed a mean of 20.8. The population standard deviation is 3.

Let $\mu$ = mean Ohio scores.

So, Null Hypothesis, $H_0$ : $\mu$ $\geq$ 21.1 {means that the mean Ohio score is above or equal the national average}

Alternate Hypothesis, $H_A$ : $\mu$ < 21.1 {means that the mean Ohio score is below the national average}

The test statistics that would be used here One-sample z test statistics as we know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n}}}$ ~ N(0,1)

where, $\bar X$ = sample mean Ohio score = 20.8

$\sigma$ = population standard deviation = 3

n = sample of Ohio = 500

So, test statistics = $\frac{20.8-21.1}{\frac{3}{\sqrt{500}}}$

= -2.24

The value of z test statistics is -2.24.

Now, at 0.1 significance level the z table gives critical value of -1.2816 for left-tailed test. Since our test statistics is less than the critical values of z as -2.24 < 1.2816, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean Ohio score is below the national average.

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3 years ago