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MatroZZZ [7]
3 years ago
12

What number is 100`000 more than seven hundred two thousand eight three

Mathematics
1 answer:
ANEK [815]3 years ago
5 0

Answer:

802,083

Step-by-step explanation:

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Use the magic penny parable to determine how much money you would have after 8 days.
Anit [1.1K]

Use the formula T(x) = 0.01x2^x

X is the number of days.

T(8) = 0.01 x 2^8

T(8) = 0.01 x 256

T(8) = $2.56

3 0
3 years ago
Help please!<br> Find perimeter and Area
MatroZZZ [7]

Answer:

P = 70 mi A = 210 mi^2

Step-by-step explanation:

Sides:

a = 29 m

b = 20 m

c = 21 m

Angles:

A = 90 °

B = 43.6028 °

C = 46.3972 °

Other:

P = 70 m

s = 35 m

K = 210 mi^2

r = 6 m

R = 14.5 m

Agenda:

A = angle A

B = angle B

C = angle C

a = side a

b = side b

c = side c

P = perimeter

s = semi-perimeter

K = area

r = radius of inscribed circle

R = radius of circumscribed circle

SSS is Side, Side, Side

Heron’s formula says that if a triangle ABC has sides of lengths a, b, and c opposite the respective angles, and you let the semiperimeter, s, represent half of the triangle’s perimeter, then the area of the triangle is

7 0
2 years ago
in sports club there are 800 members . the ratio of soccer members to social members is 5to 3 how many soccer players are there
attashe74 [19]
5:3

5+3=8
8 units

800=8 units
divide oth sides by 8
100=1 units

soccer=5 units=5 times 100=500
social=3 units=3 times 100=300



500 soccer players

5 0
3 years ago
In a bag of m&amp;m's there are 5 brown 6 yellow 4 blue 3 green and 2 orange. What's the probability of getting 3 yellow m&amp;m
olasank [31]
There are 5+6+4+3+2=20 m&m's in the bag.
Calculate in how many ways you can choose 3 m&m's from 20:
_{20} C _3=\frac{20!}{3!(20-3)!}=\frac{20!}{3! \times 17!}=\frac{17! \times 18 \times 19 \times 20}{6 \times 17!}=\frac{18 \times 19 \times 20}{6}=3 \times 19 \times 20= \\&#10;=1140

There are 6 yellow m&m's.
Calculate in how many ways you can choose 3 m&m's from 6:
_6 C _3 = \frac{6!}{3!(6-3)!}=\frac{6!}{3! \times 3!}=\frac{3! \times 4 \times 5 \times 6}{3! \times 6}=\frac{4 \times 5 \times 6}{6}=4 \times 5=20

The probability is the number of ways of choosing 3 m&m's from 6 m&m's divided by the number of ways of choosing 3 m&m's from 20 m&m's.
P=&#10;\frac{20}{1140}=\frac{20 \div 20}{1140 \div 20}=\frac{1}{57}

The probability is 1/57.
4 0
3 years ago
Can someone please help me??
butalik [34]

I do believe the answer is D

6 0
3 years ago
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