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3 years ago

Devin buys 12 candy bars for

1 answer:

8 0

Devin is buying 12 for $12 so for each he bought it was $1. If he’s selling them for the same price he bought them for (each) when he sells all 12 for $1, he will be left off with the same price he started off with. Devin is not making any profit. What i would do is sell them for $1.50, and then after each is sold, the total earnings would be $18.

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The recipe calls for 3 cups of ketchup for every 1/2 cups of mustard.

yaroslaw [1]

Answer:

6 ketchup / 1 mustard

Step-by-step explanation:

3 ketchup = 0.5 mustard

6 ketchup per 1 mustard

6 0

3 years ago

Read 2 more answers

what is the missing side in a right triangle if one leg measures 5 cm and the longest side measures 13 cm

Alika [10]

Answer:

<u>The missing side is 12 cm length</u>

Step-by-step explanation:

1. Let's review the information given to us to solve the case correctly:

Length of the longest side= 13 cm

Length of one leg = 5 cm

2. Using the Pythagorean theorem for finding the length of the second leg, because this is a right triangle:

2nd leg² = Length of the longest side ² - Length of one leg²

2nd leg² = 13 ² - 5 ²

2nd leg² = 169 -25

2nd leg² = 144

2nd leg = √144

2nd leg = 12 cm

<u>The missing side is 12 cm length</u>

3 0

3 years ago

Which of the following values does not satisfy the inequality-2x-6is less than or equal to 1 A)-4 B)-3 C)-2 D)-1

GaryK [48]

-2x - 6 < = 1
-2x < = 1 + 6
-2x < = 7...change the inequality sign when dividing by a negative number
x > = -7/2
x > = - 3.5

the one that does not satisfy the inequality is : -4...because it is less then -3.5

3 0

3 years ago

Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e^−2

Mekhanik [1.2K]

Answer:

x=1

y=s

z=1

Step-by-step explanation:

(x, y, z)=(1, 0, 1)

Substitute 0 for y

$y = e^{-2t} *sin 4t\\0 = e^{-2t} *sin 4t\\\\0 = e^{-2t} *(\frac{e^{4t}-e^{-4t}}{2j} )\\0 = e^{-2t} *(e^{4t}-e^{-4t} )\\0 = e^{-2t} *e^{4t}*(1-e^{-8t} )\\\\0 = e^{2t}*(1-e^{-8t} )\\\\\\Either \\0 = e^{2t}\\t = -inf\\or\\0 = (1-e^{-8t} )\\(e^{-8t} ) = 1\\ -8t = ln(1) =0\\t=0\\\\$

Confirming if t=0 satisfy the other equation

x = e^−2t cos 4t = e^−2(0)cos(4*0)

= e^(0)cos(0) = 1

z = e^−2t = e^−2(0) = 0

Therefore t=0 satisfies the other equation

Finding the tangent vector at t=0

$\frac{dx}{dt}=-2te^{-2t} cos4t + e^{-2t}(-4sin4t)=-2(0)e^{-2(0)} cos4(0) + e^{-2(0)}(-4sin4(0))=0\\\\ \frac{dy}{dt} =-2te^{-2t} sin4t + e^{-2t}(4cos4t)=-2(0)e^{-2(0)} sin4(0)+ e^{-2(0)(4cos4(0)) }= 1\\\\\frac{dz}{dt} = -2te^{-2t} = -2(0)e^{-2(0)} = 0$

The vector equation of the tangent line is

(1, 0, 1) +s(0,1,0)= (1, s, 1)

The parametric equations are:

x=1

y=s

z=1

6 0

3 years ago

Find the LCM of 20, 35 & 50.

Ivanshal [37]

Answer:

Answer: LCM of 20,35 and 50 is 1400

Step-by-step explanation:

5 0

2 years ago