Answer:
ρ_air = 0.15544 kg/m^3
Step-by-step explanation:
Solution:-
- The deflated ball ( no air ) initially weighs:
m1 = 0.615 kg
- The air is pumped into the ball and weight again. The new reading of the ball's weight is:
m2 = 0.624 kg
- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.
m_air = Δm = m2 - m1
m_air = 0.624 - 0.615
m_air = 0.009 kg
- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:
V_air = 4*π*r^3 / 3
V_air = 4*π*0.24^3 / 3
V_air = 0.05790 m^3
- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:
ρ_air = m_air / V_air
ρ_air = 0.009 / 0.05790
Answer: ρ_air = 0.15544 kg/m^3
8 thousands is equal to 8000.
15 hundreds is equal to 1500.
15 tens is equal to 150.
18 ones is equal to 18.
So just add them up.
8000 + 1500 = 9500.
9500 + 150 = 9650.
9650 + 18 = 9668.
The number is 9668
Given:
Consider the given expression is:
To find:
The simplified form of the given expression.
Solution:
We have,
Using distributive property, it can be written as:
Therefore, the correct option is A.
Basically you are multiplying each thing by 5
1 stage 1
5 stage 2
25 stage 3
125 stage 4
625 stage 5
3125 stage 6
