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3 years ago

If you have to get to 45,000 dollars, how many times would you have to divide by 150 to get to 45,000?

Mathematics

2 answers:

Mila [183]3 years ago

5 0

45,000/150 = 300 You would have to divide 300 times.

MrRissso [65]3 years ago

4 0

300 times........... well lets put it like this 45000/150 is 300 there"s your answer

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A cone has a radius of 5 ft and a height of 15 ft. It is empty and is being filled with water at a constant rate of 15 15 ft 3 f

kvasek [131]

Answer:

$\frac{dr}{dt}=0.11062ft/sec$

Step-by-step explanation:

From the question we are told that:

Radius $r=5ft$

Height $H=15ft$

Rate $R=15ft/3sec =5ft/s$

Surface Radius $R_{surf}=2.2ft$

Generally the equation for Volume is mathematically given by

$V=\frac{1}{3}\pi*r^2h$

Since radius to height ratio gives

$\frac{r}{h}=\frac{5}{15}$

$\frac{r}{h}=\frac{1}{3}$

$h=3r$

Therefore

$V=\frac{1}{3}\pi*r^2(3r)$

$V=\pi r^3$

Generally the equation for Change of Volume is mathematically given by

$\frac{dv}{dt}=\pi \frac{d}{dt}(r^3)$

$\frac{dv}{dt}=\pi 3*r^2 \frac{dr}{dt}$

$\frac{dv}{dt}=\pi 3*(2.2)^2 \frac{dr}{dt}$

$\frac{dr}{dt}=\frac{5}{45.62}$

$\frac{dr}{dt}=0.11062ft/sec$

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3 years ago

What's the surface area of this triangular prism

Inessa [10]

Answer:

375m²

Step-by-step explanation:

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3 years ago

How to factor 3x^2+16x-12

Yakvenalex [24]

Factor 3x^2 +16x -12

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Answer

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3 years ago

Homeroom Data of Tickets Sold:

cricket20 [7]

1. the mean is 16

2. the mean is 22.5

the formula that can be used to calculate the mean is

= sum of terms/number of terms

for the first question the mean can be calculated as follows

sum of terms= 20+15+19+16+10

= 80

number of terms= 5

mean= 80/5

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for the second question the mean can be calculated as follows

sum of terms= 19+23+11+30+27+27+22+26+16+24

= 225

number of terms= 10

mean= 225/10

= 22.5

Hence the mean for the first expression is 16 and the mean for the second expression is 22.5

Please see the link below for more information

brainly.com/question/26159926?referrer=searchResults

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bixtya [17]

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