I'm guessing that the two expressions are for separate equilateral triangles.
If so, the equations would be:
3(3x-14)=180
3(x+4)=180
to solve the first equation, divide by 3:
3x-14=60
then, add 14 to both sides:
3x=74
lastly, divide both sides by 3:
x=24.667
to solve the second equation, divide both sides by 3:
x+4=60
then, subtract 4 from both sides:
x=56
Answer:
AB is longer FD
Step-by-step explanation:
Given
See attachment for triangles ABC and FDE
Required
Compare line segments AB and FD
From the attachment, we have:
--- equal line segments
The measure of angles will then be used to compare the line segments;
The longer the angle of depression, the shorter the required line segment
implies that AB is longer
Step-by-step explanation:
Sin^2 (x) * Cos^2 (x) = {[1 - cos (2x)]/2}*{[1 + cos (2x)]/2}
Sin^2 (x) * Cos^2 (x) =[ 1 - cos^2 (2x)]/4
Sin^2 (x) * Cos^2 (x) = (1/4) - (1/4) * cos^2 (2x)
Sin^2 (x) * Cos^2 (x) = (1/4) - (1/4) * {[1 + cos (2*2x)]/2}
Sin^2 (x) * Cos^2 (x) = (1/4) - (1/8) * [1 + cos (4x)]
Sin^2 (x) * Cos^2 (x) = (1/4) - (1/8) - (1/8)* [cos (4x)]
Sin^2 (x) * Cos^2 (x) = (1/8) - (1/8)* [cos (4x)]
B the plane has only one dimension
