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2 years ago

12. Monica is an unmarried college student with no dependents. Last year, she

1 answer:

8 0

The tax bracket that Monica falls partly into is the $0 - $9,950 bracket. This is because her taxable annual earnings after is less than $9,950. hence she will be paying 10% of what's taxable.

<h3 /><h3>What is a Tax Bracket?</h3>

A tax bracket is a tax group into which a person falls into depending on their annual income, number of dependents, and marital status.

It is important to know that tax brackets are reviewed from time to time.

Learn more about Tax Brackets at:

brainly.com/question/24102952

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Airida [17]

Answer: 19.6 feet

Step-by-step explanation:

Using the Pythagorean theorem,

$x^2 +(x+6)^2 =48^2\\\\x^2 +x^2 +12x+36=2304\\\\2x^2 +12x-2268=0\\\\x^2 +6x-1134=0\\\\x=\frac{-6 \pm \sqrt{6^2 -4(1)(-1134)}}{2(1)}\\\\x \approx 30.8 \text{ } (x > 0)\\\\\implies x+(x+6) \approx 67.6\\\\\therefore (x+(x+6))-48 \approx 19.6$

4 0

1 year ago

In 2012, a health insurance plan for a 35-year-old and his or her spouse costs $301 per month. That rate increased to $430 p

katrin2010 [14]

Answer: See explanation

Step-by-step explanation:

Let the cost for insuring the applicant = a.

Let the cost for insuring the spouse = b

Let the cost for insuring the first child= c

Let the cost for insuring the second child = d

A 35-year-old health insurance plan and that of his or her spouse costs $301 per month. This means that:

a + b = $301.

That rate increased to $430 per month if a child were included. This means the cost of a child will be:

= $430 - $301

= $129

The rate increased to $538 per month if two children were included. This means the cost for the second child will be:

= $538 - $430

= $108

The rate dropped to $269 per month for just the applicant and one child. His will be the cost of the applicant and a single child. This can be written as:

a + $129 = $269

a = $269 - $129

a = $140

Since a + b = $301

$140 + b = $301

b = $301 - $140

b = $161

Applicant = $140

The spouse = $161

The first child = $129

The second child = $108

3 0

3 years ago

Which methods could you use to calculate the x-coordinate of the midpoint of

Iteru [2.4K]

Which methods could you use to calculate the x-coordinate of the midpoint of

a horizontal line segment with endpoints at (0,0) and (20, 0)?

Check all that apply.

C. Count by hand

3 0

3 years ago

If L=√(x^2+y^2), dx/dt =-4, dy/dt=3, find dL/dt when x=4 and y=3

yulyashka [42]

Hello,

$L=\sqrt{x^2+y^2} \\\\\dfrac{dx}{dt}=-4\\\\\dfrac{dy}{dt}=3\\\\x=4, y=3\\\\\dfrac{\partial L} {\partial x} =\dfrac{x}{\sqrt{x^2+y^2}} \\\\\dfrac{\partial L} {\partial y} =\dfrac{y}{\sqrt{x^2+y^2}} \\\\\dfrac{dL}{dt} =\dfrac{\partial L} {\partial x}*\dfrac{dx}{dt}+\dfrac{\partial L} {\partial y}*\dfrac{dy}{dt}\\\\=-4*\frac{-4}{\sqrt{4^2+3^2}} +3*\frac{3}{\sqrt{4^2+3^2}}\\\\=\dfrac{16}{5} +\dfrac{9}{5} \\\\=5\\$

5 0

3 years ago

How would you match these up?

TEA [102]

<h3>Answer: Bottom right corner (ie southeast corner)</h3>

This 3D solid is a strange sideways bowl shape. Each cross section is a ring to show the empty space.

======================================================

Explanation:

Check out the diagram below. The graph was created with GeoGebra. We have y = x^2 in red and x = y^2 in blue.

The gray region is the region between the two curves. We spin this gray region around the horizontal green line y = 1 to generate the answer mentioned above.

Note how (1,1) is a fixed point that does not move as this is on the line y = 1. Every other point moves to sweep through 3D space to create the solid figure. One way you can think of it is to think of propeller blades. Or you can think of a revolving door (the door is "flat" so to speak, but it sweeps out a 3D solid cylinder).

5 0

3 years ago