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2 years ago

Given h(x) = 3(2 – X), what is the value of h(-4)? 4.-6 B. 10 C.2 D.18

Mathematics

2 answers:

GaryK [48]2 years ago

7 0

C. 2

I hope this can help you

worty [1.4K]2 years ago

6 0

Answer:

Step-by-step explanation:

substitute x = - 4 into h(x)

h(- 4) = 3(2 - (- 4) ) = 3(2 + 4) = 3 × 6 = 18

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Use the summation formulas to rewrite the expression without the summation notation. summation_k = 1^n 12k(k - 1) / n^3 Use the

kvasek [131]

Answer:

$Sum=4*[\frac{n^2-1}{n^2}]$

For n=10:

Sum=3.96

For n=100:

Sum=3.9996

For n=1000:

Sum=3.999996

For n= 10000:

Sum=3.99999996

Step-by-step explanation:

Formula:

$\sum_{k=1}^n \frac{12k(k-1)}{n^3}$

Rearranging the above formula:

$\sum_{k=1}^n \frac{12}{n^3}*k(k-1)\\\sum_{k=1}^n \frac{12}{n^3}*(k^2-k)$ Eq (1)

According to summation formula:

$\sum_{k=1}^n\ k= \frac{n(n+1)}{2}\\ \sum_{k=1}^n\ k^2= \frac{n(n+1)(2n+1)}{6}\\$

Putt these in Eq (1), and we will get:

$=\frac{12}{n^3}[\frac{n(n+1)(2n+1)}{6}-\frac{n(n+1)}{2}]\\Taking\ n\ as\ common\\=n*\frac{12}{n^3}[\frac{(n+1)(2n+1)}{6}-\frac{(n+1)}{2}] \\=\frac{12}{n^2}*[\frac{(n+1)(2n+1)}{6}]-\frac{12}{n^2}*[\frac{(n+1)}{2}] \\=\frac{2*(n+1)(2n+1)}{n^2}-\frac{6(n+1)}{n^2}\\$

Taking $2(n+1)$ as common:

$=2(n+1)*\frac{2n+1-3}{n^2} \\=(2n+2)*\frac{2n-2}{n^2}\\=\frac{4n^2-4}{n^2}$

After more simplifying,

$Sum=4*[\frac{n^2-1}{n^2}]$

Now ,for n=10:

$Sum=4[\frac{(10^{2})-1}{10^{2}}]\\Sum=3.96$

For n=100:

$Sum=4[\frac{(100^{2})-1}{100^{2}}]\\Sum=3.9996$

For n=1000

$Sum=4[\frac{(1000^{2})-1}{1000^{2}}]\\Sum=3.999996$

For n=10000:

$Sum=4[\frac{(10000^{2})-1}{10000^{2}}]\\Sum=3.99999996$

4 0

3 years ago

(0.0196N) x (0.016m) =

Anettt [7]

Answer: $0.0003136\ J$ or $3.136*10^{-4}J$

Step-by-step explanation:

By definiition, when you multiply 1 Newton (N) by 1 meter (m), the unit obtained is an unit called "Joule", whose symbol is J.

Joule (J) is an unit of energy, work or heat.

Then to solve the exercise, you must multiply 0.0196 N by 0.016 m. Therefore, you obtain that the product is:

$(0.0196N)(0.016m)=0.0003136J$ or $3.136*10^{-4}J$

8 0

3 years ago

Read 2 more answers

help me pls i don't have many points pls help if you don't believe me go to my acc and look at my points i only have 13

miss Akunina [59]

Answer:

1. 14

2. 17.5

3. 60

4. 238

5. 91.4375

6. 58.065

Step-by-step explanation:

Sorry, I'm only doing 6, GOOD LUCK!!!

4 0

3 years ago

What is the greatest common factor of 9x^2 2 and 6x?

zheka24 [161]

Answer:

The greatest common factor is 1.

Step-by-step explanation:

In this question we will factorize the expressions given and select the common factors among all.

For 9x² = 1×3×3×X×X

For 2 = 1×2

For 6x = 1×2×3×X

So we find the common factor in all expressions is = 1

Answer is 1.

7 0

3 years ago

What is the probability that a point chosen at random in the triangle is also in the blue square?

matrenka [14]

The probability that a point chosen at random in the triangle is also in the blue square can be calculated using geometrical definition of the probability:

$Pr=\dfrac{\text{desired area}}{\text{total area}}.$

1. Find the total area of the triangle:

$A_{total}=\dfrac{1}{2}\cdot 6\cdot 9=27\ in^2.$

2. Find the desired area of the square:

$A_{desired}=3\cdot 3=9\ in^2.$

Then the probability is

$Pr=\dfrac{9}{27}=\dfrac{1}{3}.$

Answer: correct choice is B

8 0

3 years ago