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gayaneshka [121]
3 years ago
11

What is the volume of the prism?

Mathematics
2 answers:
miskamm [114]3 years ago
8 0

Answer: V=1332 in. cubed

Step-by-step explanation:

V=Bh

V=3996*1/3

V=1332 in.cubed

SOVA2 [1]3 years ago
6 0

Answer:

148 in³

Step-by-step explanation:

The equation for the volume of a cube is V = a^{3}

Here, a = \frac{1}{3}.

V=\frac{1}{3} ^{3}

V = \frac{1}{27}

So, the volume of each cube is \frac{1}{27} in.

The prism is filled completely with 3996 of these cubes.

3996*\frac{1}{27} = 148

The volume of the prism is 148 in³.

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Solve. Write your answer in interval notation.
lina2011 [118]

Answer: x < 3 or x ≥ 11

(-∞, 3) or [11, ∞)

Step-by-step explanation:

subtract 4 from each side

2x < 6 .     or .         3x  ≥ 33

x < 3 or x ≥ 11

make sure you have an OPEN DOT at 3 pointing to negative infinity and a CLOSED DOT at 11 pointing to positive infinity.  

3 0
3 years ago
98 PTS!<br> Can someone please help?
padilas [110]

Answer: -22


Step-by-step explanation:

In the first question, we can simplify 2√8 to 4√2, making it :

(√10 + 4√2)(√10 - 4√2)

When you FOIL, √10(√10) = 10, and 4√2 * -4√2 = -32. The others cancel each other out. So -32 + 10 = -22.



5 0
3 years ago
Read 2 more answers
Write as a single term: cos(2x) cos(x) + sin(2x) sin(x)
GREYUIT [131]

Answer: cos(x)

Step-by-step explanation:

We have  

sin ( x + y ) = sin(x)*cos(y) + cos(x)*sin(y)   (1)   and

cos ( x + y ) = cos(x)*cos(y) - sin(x)*sin(y)  (2)

From eq. (1)

if x = y

sin ( x + x ) = sin(x)*cos(x) + cos(x)*sin(x) ⇒ sin(2x) = 2sin(x)cos(x)

From eq. 2

If x = y

cos ( x + x ) = cos(x)*cos(x) - sin(x)*sin(x)  ⇒ cos²(x) - sin²(x)

cos (2x) = cos²(x) - sin²(x)

Hence:The expression:

cos(2x) cos(x) + sin(2x) sin(x)  (3)

Subtition of sin(2x) and cos(2x)  in eq. 3

[cos²(x)-sin²(x)]*cos(x) + [(2sen(x)cos(x)]*sin(x)

and operating

cos³(x) - sin²(x)cos(x) + 2sin²(x)cos(x) = cos³(x) + sin²(x)cos(x)

cos (x) [ cos²(x) + sin²(x) ]  = cos(x)

since cos²(x) + sin²(x) = 1

8 0
3 years ago
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larisa [96]
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3 years ago
Which expressions below are equivalent to
Yuri [45]

Answer:

<h2>A, B, D, E</h2>

Step-by-step explanation:

2(2x + 1) = (2)(2x) + (2)(1) = 4x + 2 → A

<em>used distributive property</em>

2(2x + 1) = 2(1 + 2x) → B

<em>used commutative property</em>

2(2x + 1) = (2x + 1) + (2x + 1) = 2x + 1 + 2x + 1 → D

<em>used 2a = a + a</em>

2(2x + 1) = 4x + 2 = x + x + x + x + 1 + 1 → E

<em>used 4x = x + x + x + x and 2 = 1 + 1</em>

6 0
3 years ago
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