The statement that Cascading style sheets (CSS) use special hypertext markup language (HTML) tags to globally define font characteristics for a variety of page elements as well as how those elements are laid out on a web page is true. <span> CSS is a stylesheet language used to describe the presentation of a document written in HTML or XML.</span>
Answer:
Java in JavaScript does not correspond to any relationship with Java programming language.
Explanation:
The prefix Java in Javascript is there for historical reasons.
The original internal name of Javascript when it was created by Brendan Eich at Netscape was Mocha. This was released to public as Livescript in 1995. The name Livescript was eventually changed to Javascript in Netscape Navigator 2.0 beta 3 release in December 1995 after Netscape entered into an agreement with Sun Microsystem. The primary purpose of change of name seemed to be as a marketing aid to benefit from the growing popularity of Java programming language at that time.
Big-O notation is a way to describe a function that represents the n amount of times a program/function needs to be executed.
(I'm assuming that := is a typo and you mean just =, by the way)
In your case, you have two loops, nested within each other, and both loop to n (inclusive, meaning, that you loop for when i or j is equal to n), and both loops iterate by 1 each loop.
This means that both loops will therefore execute an n amount of times. Now, if the loops were NOT nested, our big-O would be O(2n), because 2 loops would run an n amount of times.
HOWEVER, since the j-loop is nested within i-loop, the j-loop executes every time the i-loop <span>ITERATES.
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As previously mentioned, for every i-loop, there would be an n amount of executions. So if the i-loop is called an n amount of times by the j loop (which executes n times), the big-O notation would be O(n*n), or O(n^2).
(tl;dr) In basic, it is O(n^2) because the loops are nested, meaning that the i-loop would be called n times, and for each iteration, it would call the j-loop n times, resulting in n*n runs.
A way to verify this is to write and test program the above. I sometimes find it easier to wrap my head around concepts after testing them myself.
Answer:
If you are trying to put the events in order and they are out of order you will probaly get the question wrong so make sure the events are in order.
Explanation:
