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3 years ago

What polynomial function could be represented by the graph below

Mathematics

2 answers:

zzz [600]3 years ago

7 0

Answer: (B). F(x) = 2x² + 2x - 4

Step-by-step explanation:

Let us think about the parent function F(x) = x² to pick our answer.

Options A and C have only shifted 2 units down (showed by the "-2" at the end) and the function graphed is shifted four units down.

Between options B and D, one is shifted 2 units to the right, and one is shifted 2 units to the left. We need the one shifted 2 units to the left. This is shown by the "+2x" in option B meaning it is our answer.

kotegsom [21]3 years ago

3 0

Answer:

(B). F(X)=2x^2+2x-4

Step-by-step explanation:

-4 means it passes through -4 at the y axis

B and D have -4

graph passes thru x axis at -2 and 1

if you enter x = -2 or 1 in the formula

(B). F(X)=2x^2+2x-4

you get 0

it's not D because when you enter -2 or 1 for x

you don't get 0

you get 8 and -4

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4 years ago

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finlep [7]

Answer:

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Step-by-step explanation:

We have been given four options and we are asked to choose the option that represents the best deal.

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3 years ago

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taurus [48]

Answer:

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Step-by-step explanation:

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3 years ago

Pls solve this question

just olya [345]

Answer:

${( \sqrt{ {x}^{ - 3} }) }^{5} = ({( {x}^{ - 3}) }^{ \frac{1}{2} } ) ^{5} \\ \\ = {x}^{ - 3 \times \frac{1}{2} \times 5} = {x}^{ - \frac{15}{2} } = \frac{1}{ {x}^{ \frac{15}{2} } }$

<em><u>Or ;</u></em>

${( \sqrt{ {x}^{ - 3} } )}^{5} = {( \sqrt{ \frac{1}{ {x}^{3} }} })^{5} = ( { \frac{ \sqrt{1} }{ \sqrt{ {x}^{3} } } })^{5} \\ \\ = ( { \frac{1}{ \sqrt{x} \sqrt{ {x}^{2} } } })^{5} = ({ \frac{1}{ x\sqrt{x} }})^{5} \\ \\ = ( \frac{ {(1)}^{5} }{ {x}^{5} ( \sqrt{x} )^{5} } ) = \frac{1}{ {x}^{5} \times {x}^{ \frac{1}{2} \times 5 } } \\ \\ = \frac{1}{ {x}^{5} \times {x}^{ \frac{5}{2} } } = \frac{1}{ {x}^{5} \sqrt{ {x}^{5} } } \\ \\ = \frac{1}{ {x}^{5} \sqrt{ {x}^{4} {x}^{1} } } = \frac{1}{ {x}^{5} \sqrt{x} \sqrt{( { {x}^{2} })^{2} } } \\ \\ = \frac{1}{ {x}^{5} {x}^{2} \sqrt{x} } = \frac{1}{ {x}^{7} \sqrt{x} } = \frac{ \sqrt{x} }{ {x}^{8} }$

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2 years ago

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geniusboy [140]

I'm pretty there's a complement

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4 years ago