The figure shown is a rectangle. If you draw a new rectangle in which the dimensions are doubled, what is the relationship betwe
en the AREAS of the two rectangles? A) The area of the new rectangle is twice that of the original rectangle. B) The area of the new rectangle is one-half that of the original rectangle. C) The area of the new rectangle is four times that of the original rectangle. D) The area of the new rectangle is eight times that of the original rectangle.
1 answer:
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Answer:
length = 35ft, width = 20ft
Step-by-step explanation:
We are working with length (L), width (W), and area (A). We are asked to find the 2 dimensions. The question tells us that L = W + 15, so we can express L in terms of W. However, we still don't know what A is. Since we have 2 unknowns, we somehow need to develop 2 equations to get a solvable system.
We can set up the first equation using the relationship between L and W:
We can set up the second equation using the information in the second sentence:
Now we can plug the first equation, already isolated for A, into the second equation and solve for W:
A pretty nasty-looking equation actually becomes pretty easy to solve. We know the length is 15ft greater than the width, so if W=20, L=35.
Answer: b= 11.2
10^2 + b^2 = 15^2
100 + b^2 = 225
b^2 = 125
b=
b= 11.2
Step-by-step explanation: