Please help ASAP I’m very unsure on how to do these 2 questions please give answers for both :)
2 answers:
Answer:
1) Option 2
2) Option 1
Step-by-step explanation:
1) 3a-2b
<u><em>Where a = 3, b = 2</em></u>
=> 3(3)-2(2)
=> 9-4
=> 5
2) 5c+3d
<u><em>Where c = 4, d = -5</em></u>
=> 5(4) + 3(-5)
=> 20 - 15
=> 5
Answers:
5, 5
Step-by-step explanation:
<u>Put a as 3 and b as 2 and evaluate:</u>
3(3) - 2(2)
9 - 4
= 5
<u>Put c as 4 and d as -5 and evaluate:</u>
5(4) + 3(-5)
20 - 15
= 5
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Solution :
Given :
X = the number of boys in a family of four children
Families having four children are chosen randomly.
The gender distribution in the four child family are equally probable.
Thus,
X P(X) CDF
0 
= 1/16 
1 
= 1/4 
2 
= 3/8 
3 
= 1/4 
4 
= 1/16 1
Answer:
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Answer:
it's 12 because
2×6=12
3×4=12
4×3=12
and all of them have twelve
Answer:
d. -7 1/8, -3.62, -1/2, 0, 1.75
Step-by-step explanation:
