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gulaghasi [49]
2 years ago
12

How much would you pay for Light Oak wood floors at $2.76 per sqft for a room that is 14 X 16?

Mathematics
1 answer:
Alchen [17]2 years ago
8 0

Answer:

$618.24

Step-by-step explanation:

The area of the room is 224. Then for each square feet is 2.76 do multiplying that you get the answer.

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I need the answer plzz now
Verizon [17]

Answer:

Ea and St

Step-by-step explanation:

6 0
3 years ago
Sasha packed unit cubes into a prism, as shown. Which statement about the volume of the box is true.
Zina [86]

Answer:

The answer is " The volume is greater than 50 cubic units "

Step-by-step explanation:

In this question, the value of the units and figure is missing that's why its solution can be defined as follows:

Let's the unit value =50 and please find the figure in the attachment file.

The given figure shows its box is not filled with 50 cubes. These were ten empty places where cubes could be placed.

This figure indicates that only the box size will be four units per five units per three units, so they realize it will be in...

\to (4 \times 5 \times  3) \ units^3 = 60 \ units^3

That's why the volume value exceeds 50 cubic units.

6 0
2 years ago
12 bags of M&Ms cost $18. How much does it cost for 5 bags​
musickatia [10]

Answer:

$7.50

Step-by-step explanation:

18 divided by 12= 1.5 1.5x5 = 7.5

6 0
3 years ago
Read 2 more answers
Is there more wood in a 60​-foot-high tree trunk with a radius of 2.2 feet or in a 50​-foot-high tree trunk with a radius of 2.6
Sladkaya [172]

Answer:

V₂=1061.85 ft³

Step-by-step explanation:

To determine where more wood is found, just find the volume of each log and see which one has the largest volume

knowing that the volume of a straight cylinder is

V=πR²h, where R=radius and h=height

V_{1}=\pi  (2.2)^{2}60= 912.31ft^{3}\\V_{2}=\pi  (2.6)^{2}50= 1061.85ft^{3}

As we can observe

V₂>V₁

7 0
3 years ago
Will someone please help me !
mr_godi [17]
1: = 12x-39
2 = -11d+44
3 = 20y-15
4 = -22
5 = -4m+4
6 = 13h+21
7 = -6g+3
8= 13c-20
9 = -2q+12 
your welcome cutie ;)
5 0
3 years ago
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