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Rashid [163]
2 years ago
7

If you roll two fair six sided dice, what is the probability that the sum is 5 or lower

Mathematics
1 answer:
lana66690 [7]2 years ago
4 0

Answer: P(sum is 5 or lower) = 10/36 (not simplified) = 5/18 (simplified)

Step-by-step explanation: The event is {(1,1), (1,2), (1,3), (1,4), (2,1), (2,2), (2,3), (3,1), (3,2), (4,1)}

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Area model division 246÷3
lord [1]
246 divided by 3 should equal 82
4 0
3 years ago
Let f ( x ) = 2 x − 1 , g ( x ) = 3 x , and h ( x ) = x ^2 + 1 , what is h( h ( 5) ) ?
strojnjashka [21]
First you would solve for h(5) by plugging in 5 as your x, then solving it.

h(5) = 5^2 + 1
h(5) = 25 + 1
h(5) = 26

Next you would multiply the 26 by the individual h, which is basically h(1).

h(1) = 1^2 + 1
h(1) = 2

Lastly you multiply your h(1) value by the h(5) value to get your answer.

h(1) • h(5) = 26 • 2
h[h(5)] = 52
7 0
3 years ago
. In the past decades there have been intensive antismoking campaigns sponsored by both federal and private agencies. In one stu
Sergeeva-Olga [200]

Answer: B. H_0:p_1=p_2

H_a:p_1>p_2

Step-by-step explanation:

Let p_1 be the proportion of all U.S. adults that smoked in 1995. Let p_2 denote the proportion of all U.S. adults that smoked in 2000.

Objective for the study : Whether the proportion of U.S. adults that smoke declined during the 5-year period between the samples.

i.e. p_1>p_2

Alternative hypothesis(H_a) is the statement containing population  parameter that shows there is significant difference between the groups being tested.

⇒ H_a:p_1>p_2

Null hypothesis(H_0) is the statement containing population parameter that shows there is no significant difference between the groups being tested.

⇒ H_0:p_1=p_2

Hence, The hypotheses to test in this problem are

H_0:p_1=p_2

H_a:p_1>p_2

Hence, the correct answer is B. H_0:p_1=p_2

H_a:p_1>p_2

8 0
3 years ago
Mia opens a new savings account with $675 from her birthday last week.
IRISSAK [1]

Answer:

$891

Step-by-step explanation:

This is Your Answer: $891, Steps below

6 0
2 years ago
100 points please help will give brainliest
Dominik [7]

Answer:

The two angles ADB and BDC are congruent since they are both right angles.

The segment AD and CD are congruent since D is the midpoint of AC.

Segment BD is in common for the two triangles.

The triangles ABD and BCD are congruent by SAS. In particular, Angle A is congruent to angle C (they are opposite to congruent sides), QED

3 0
2 years ago
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