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2 years ago

If you roll two fair six sided dice, what is the probability that the sum is 5 or lower

Mathematics

1 answer:

lana66690 [7]2 years ago

4 0

Answer: P(sum is 5 or lower) = 10/36 (not simplified) = 5/18 (simplified)

Step-by-step explanation: The event is {(1,1), (1,2), (1,3), (1,4), (2,1), (2,2), (2,3), (3,1), (3,2), (4,1)}

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What is 10 times as much as 3.457?

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Answer:

discuss two ways in which some cultural views that exist may affect a relationship negatively

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3 years ago

Read 2 more answers

1.Assume that 20 squirrels are put in an enclosed wildlife ranch and the squirrel population grows for the next 5 years, as show

stiv31 [10]

Answer:

For the first group we have the pairs:

year population

0 20

1 80

2 320

3 1,280

4 5,120

5 20,480

Here we can see that the population quadruples each year

(4*20 = 80, 80*4 = 320, 320*4 = 1,280, etc...)

then the population equation is:

P(0) = 20

P(1) = 20*4

P(2) = (20*4)*4 = 20*4^2

We already can see the pattern, then we can write this relationship as:

P(t) = A*(4)^(t)

Where:

t represents time in years, and A is the initial population, that we know it is 20, then:

P(t) = 20*(4)^t

This is the function that represents the table.

B) Now we have a group of 20 squirrels and the population triples each year, with the same reasoning than before we can write the equation that models this situation as:

Q(t) = 20*(3)^t

C) Now, if the initial population of the second group is 40, the equation becomes:

Q(t) = 40*(3)^t

The population by year 3 is given by replacing t by 3, then:

Q(3) = 40*(3)^3 = 1080

And the population of the other group in year 3 is seen in the table, it is 1,280, then the population of the first group is bigger by year 3, and it is greater by:

1,280 - 1,080 = 200

So the first group is larger by 200 squirrels.

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3 years ago

Y=(x^2-6x+14) Labeling the vertex

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I leaerned this neat trick
you don't need to convert to vertex form

where
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by inserting the x value of the vertex into the equation

so

1x^2-6x+14
-b/2a=-(-6)/2(1)=6/2=3
plug that in
y=x^2-6x+14
y=3^2-6(3)+14
y=9-18+14
y=5

the vertex is (3,5)

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3 years ago

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