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RUDIKE [14]
3 years ago
10

Help me please I need this in by tomorrow

Mathematics
1 answer:
galina1969 [7]3 years ago
4 0

Answer:

BDA=29°, BCD=72°

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Find the solution of the system of equations.<br> 10x+10y=40 <br> 5x+3y=8
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Answer:

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Step-by-step explanation:

10x+10y=40

10x+10y+ -10y=40+-10y

10x=-10y+40

\frac{10x}{10} =\frac{-10y+40}{10}

x=-y+4

5x+3y=8

5(-y+4)+3y=8

-2y+20=8

-2y+20+-20=8+-20

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\div2

y=6

x=-y+4

x=-6+4

x=-2

Hope this helps.

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