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3 years ago

Find an equation for the family of linear functions with slope 5.

Mathematics

1 answer:

blondinia [14]3 years ago

7 0

These linear functions would be in the form ƒ(x) = 5x + c, where c is an arbitrary constant.

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(Pls help will give brainliest its urgent!!) Michael spends $24 each week on private swimming lessons.

vredina [299]

Answer:

i only know it is c and e but dont know about a and b

Step-by-step explanation:

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3 years ago

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How to change .365 to a percent

KATRIN_1 [288]

Multipl .365 by 100 and you get 36.5%

3 0

3 years ago

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Answers for both boxes please

sleet_krkn [62]

Answer:

x = -5 y = -3

Step-by-step explanation:

-3x + 2y = 9

multiply the 2nd equation by 3 to set it up for elimination

3(x - 3y)= 3(4)

3x-9y = 12

so now combine both to add

-3x + 2y = 9

3x - 9y = 12

Adding both gives you

-7y = 21

divide both by -7 and you get

y = -3

and you substitute y back into equation to get x

x - 3 (-3) = 4 gives you

x + 9 = 4

x = 4 - 9

x = -5

7 0

3 years ago

What is the slope of the line given by the equation y=-1/3x? Entee your answer as an integer or fraction in lowest terms.

Serhud [2]

-1/3

really? it's that easy dude.

whatever number is next to x, like say, 3x, that number would be the slope, so it would be 3.

hope it helped.

6 0

3 years ago

What is the maximum value of the objective function, P, with the given constraints?

maksim [4K]

Answer:

Option C - 420

Step-by-step explanation:

Given : Objective function, P, with the given constraints

$P=20x+35y$

Constraints,

$x+y \leq 12$

$5x+y \leq 20\\x \geq 0\\y \geq 0$

To find : What is the maximum value

Solution :

First we plot the graph through the given constrains.

As they all move towards the origin the common region of the equations is given by the points (0,0), (0,12), (2,10), (4,0)

Refer the attached figure.

So, we put all the points in P to, get maximum value.

$P=20x+35y$

Point (0,0)

$P=20(0)+35(0)=0$

$P=20x+35y$

Point (0,12)

$P=20(0)+35(12)=420$

Point (2,10)

$P=20(2)+35(10)=40+350=390$

Point (4,0)

$P=20(4)+35(0)=80$

Therefore, The value is maximum 420 at (0,12)

So, Option C is correct.

8 0

3 years ago