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Kitty [74]
3 years ago
9

Jon and Becky measured the circle shaped part of a sun they drew on the sidewalk. The diameter of the circle is 53 centimeters.

What is the approximate area of circle? ( use 3.14)
Mathematics
2 answers:
svetoff [14.1K]3 years ago
7 0

Answer:

  A: 3,017.54 cm

Step-by-step explanation:

What is the approximate area of the circle? (Use 3.14 for ).

A.3,017.54 cm?

B. 12,070.16 cm?

C. 194.68 cm2

D. 754.385 cm?

UNO [17]3 years ago
3 0
Hello!

To find the area, we use the formula A=pir², where pi=3.14 and r= the radius.

To solve, we find half of the diameter, which is the radius. Half of 53 is 26.5. We square this number and then multiply it by pi. 26.5·26.5=702.25. Now we multiply by pi. 702.25·3.14=2,205.065.

Our final answer is about 2,205.1 cm².

I hope this helps!
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A gumball has a diameter that is 66 mm. The diameter of the gumball's spherical hollow core is 58 mm. What is the volume of the
grigory [225]

Answer:

Volume of gumball without including its hollow core is 48347.6 cubic mm.

Step-by-step explanation:

Given:

Diameter of Gumball = 66 mm

Since radius is half of diameter.

Radius of gumball = \frac{diameter}{2}=\frac{66}{2} =33 \ mm

Now We will first find the Volume of Gumball.

To find the Volume of Gumball we will use volume of sphere which is given as;

Volume of Sphere = \frac{4}{3}\pi r^3

Now Volume of Gumball = \frac{4}{3}\times3.14 \times (33)^3 = 150456.24 \ mm^3

Also Given

Diameter of gumball's spherical hollow core = 58 mm

Since radius is half of diameter.

Radius of gumball's spherical hollow core = \frac{diameter}{2}=\frac{58}{2} =29 \ mm

Now We will find the Volume of gumball's spherical hollow core.

Volume of Sphere = \frac{4}{3}\pi r^3

So Volume of gumball's spherical hollow core = \frac{4}{3}\times3.14 \times (29)^3 = 102108.61 \ mm^3

Now We need to find volume of the gumball without including its hollow core.

So, To find volume of the gumball without including its hollow core we would Subtract Volume of gumball spherical hollow core from Volume of Gumball.

volume of the gumball without including its hollow core = Volume of Gumball - Volume of gumball's spherical hollow core = 150456.24\ mm^3 - 102108.61\ mm^3 = 48347.63\ mm^3

Rounding to nearest tenth we get;

volume of the gumball without including its hollow core = 48347.6\ mm^3

Hence Volume of gumball without including its hollow core is 48347.6 cubic mm.

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Answer:

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Step-by-step explanation:

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LenaWriter [7]
Easy peasy


the average rate of change in section A is the slope from (1,g(1)) to (2,g(2))
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A.

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section A has an average rate of change of 24
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