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gayaneshka [121]
2 years ago
13

PLEASEEE HELPPPP!!!!!!!!!skkaksks

Mathematics
1 answer:
Vesnalui [34]2 years ago
6 0

Step-by-step explanation:

  1. (√3+√7)(√3+√7)
  2. (√3)^2+[(√3*√7)+(√3*√7)]+(√7)^2
  3. 3+2√21+7
  4. 10+2√21
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Step-by-step explanation:

I apoligize but try googling 5% of 50

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The purpose of a statistical quality control chart is to identify when assignable causes of variation have entered the productio
MAXImum [283]

Answer:

TRUE

Step-by-step explanation:

Control charts employ the use of graphical displays to observe and monitor a process which could be either a manufacturing, production or business process to ensure that it is in a sate of control using statistical analysis. This graphical display will enable the visualization of interference or variation dues to certain causes or factors which might creep in to effect an unwanted variation in the production or business process. Hence, with the control chart, these variations would be detected and corrected to ensure that the production proesss is free from unwanted interference as much as possible.

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3 years ago
Determine the possible survey questions that could be used to collect​
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where would the survey be?

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3 years ago
Solve the system of equation by guess sidle method
lilavasa [31]

Answer: The solution is,

x_1\approx 0.876

x_2\approx 0.419

x_3\approx 0.574

Step-by-step explanation:

Given equations are,

8x_1 + x_2 + x_3 = 8

2x_1 + 4x_2 + x_3 = 4

x_1 + 3x_2 + 5x_3 = 5,

From the above equations,

x_1=\frac{1}{8}(8-x_2-x_3)

x_2=\frac{1}{4}(4-2x_1-x_3)

x_3=\frac{1}{5}(5-x_1-3x_2)

First approximation,

x_1(1)=\frac{1}{8}(8-(0)-(0))=1

x_2(1)=\frac{1}{4}(4-2(1)-(0))=0.5

x_3(1)=\frac{1}{5}(5-1-3(0.5))=0.5

Second approximation,

x_1(2)=\frac{1}{8}(8-(0.5)-(0.5))=0.875

x_2(2)=\frac{1}{4}(4-2(0.875)-(0.5))=0.4375

x_3(2)=\frac{1}{5}((0.875)-3(0.4375))=0.5625

Third approximation,

x_1(3)=\frac{1}{8}(8-(0.4375)-(0.5625))=0.875

x_2(3)=\frac{1}{4}(4-2(0.875)-(0.5625))=0.421875

x_3(3)=\frac{1}{5}(5-(0.875)-3(0.421875))=0.571875

Fourth approximation,

x_1(4)=\frac{1}{8}(8-(0.421875)-(0.571875))=0.875781

x_2(4)=\frac{1}{4}(4-2(0.875781)-(0.571875))=0.419141

x_3(4)=\frac{1}{5}(5-(0.875781)-3(0.419141))=0.573359

Fifth approximation,

x_1(5)=\frac{1}{8}(8-(0.419141)-(0.573359))=0.875938

x_2(5)=\frac{1}{4}(4-2(0.875938)-(0.573359))=0.418691

x_3(5)=\frac{1}{5}(5-(0.875938)-3(0.418691))=0.573598

Hence, by the Gauss Seidel method the solution of the given system is,

x_1\approx 0.876

x_2\approx 0.419

x_3\approx 0.574

4 0
3 years ago
The photo contains the question​
Sladkaya [172]

Answer:

all the answers are there in safari and also can refer to your text book

Step-by-step explanation:

8 0
3 years ago
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