The relationship of arcs is:
S '/ S = ((1/9) * pi * r) / (2 * pi * r)
Rewriting we have:
S '/ S = ((1/9)) / (2)
S '/ S = 1/18
Therefore, the area of the shaded region is:
A '= (S' / S) * A
Where A: area of the complete circle:
Clearing we have:
A = (A ') / (S' / S)
Substituting:
A = ((1/2) pi) / (1/18)
A = ((18/2) pi)
A = (9pi)
Answer:
The area of the circle is:
A = (9pi)
12 × 9 = 108
36 × 3 = 108
2 × 54 = 108
As many as possible.
Answer:
i) D: All real numbers
ii) R: 
iii) Y-int: b=2
Step-by-step explanation:
i) The given absolute value function is

The domain is all values of x that makes the function defined.
The absolute value function is defined for all values of x.
The domain is all real numbers.
ii) The given function is 
The function has vertex
.
The function is reflected in the x-axis.
This means the vertex is the maximum point on the graph of the function.
The maximum y-value is 5.
The range is therefore
or ![(-\infty,5]](https://tex.z-dn.net/?f=%28-%5Cinfty%2C5%5D)
iii) To find the y-intercept, put
into the function.




The y-intercept is (0,2) or 
See attachment for graph.
PEMDAS
-6-4(3x2)+5^2
-6-4(6)+5^2
distribute
-6-24+5^2
-6-24+25= -5
Answer:

Step-by-step explanation:
You can think of this as adding the area of the rectangular portion of the deck (length x width) and the semicircular portion (πr^2)/2.
(l×w)+(πr^2)/2
(10×7)+((π2^2)/2
79+2π
