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Zepler [3.9K]
2 years ago
6

A) Complete the histogram. b) Work out the total number of members of the club. members

Mathematics
1 answer:
Dahasolnce [82]2 years ago
3 0

Answer:

                                 

Step-by-step explanation:

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Christopher Columbus set sail from Spain in 1492. In what year did the Civil War end?
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May 9, 1865

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Plssss answer! Your team is renting a photo booth for the 8th grade dance, but you have to buy the photo paper and other supplie
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$215.25

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3 years ago
Every person has blood type O, A, B, or AB. A random group of people are blood-typed, and the results are shown in the table.
vova2212 [387]

The probability that a randomly chosen person from this group has type B is <u>3/25</u>

The probability that a randomly chosen person from this group has type AB is <u>1/25</u>

The probability that a randomly chosen person from this group has type B or type AB blood is <u>4/25</u>

8 0
3 years ago
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What is the surface area of the triangular prism?
Minchanka [31]

Answer: = 40 . 24

Step-by-step explanation:

A triangular prism. The rectangular sides are 24 feet by 40 feet, 40 feet by 15 feet, and 40 feet by 15 feet. The triangular sides have a base of 24 feet and height of 9 feet.

2,001 square feet

2,376 square feet

2,592 square feet

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4 0
2 years ago
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Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?
Bogdan [553]

Step-by-step explanation:

\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}

\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}

\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}

\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}

Taking sin²θ common in both numerator & denominator, We get :

\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{cot\theta = \dfrac{cos\theta}{sin\theta}}}}

\mathsf{\implies \dfrac{1 -cot^2\theta}{1 + cot^2\theta}}

\mathsf{Given :\;cot\theta = \dfrac{1}{\sqrt{5}}}

\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}

\mathsf{\implies \dfrac{1 - \dfrac{1}{5}}{1 + \dfrac{1}{5}}}

\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}

\mathsf{\implies \dfrac{5 - 1}{5 + 1}}

\mathsf{\implies \dfrac{4}{6}}

\mathsf{\implies \dfrac{2}{3}}

<u>Hence</u><u>,</u><u> option</u><u> </u><u>(</u><u>a)</u><u> </u><u>2</u><u>/</u><u>3</u><u> </u><u>is </u><u>your</u><u> </u><u>correct</u><u> </u><u>answer</u><u>.</u>

3 0
2 years ago
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