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julsineya [31]
3 years ago
12

Yoko, Rafael, and Jim sent a total of 100 text messages during the weekend. Yoko sent 5 more messages than Jim. Rafael sent 3 ti

mes as many messages as Jim. How many messages did they each send?
Mathematics
1 answer:
slavikrds [6]3 years ago
7 0

Answer: Yoko=24, Rafael=57, Jim=19

<u>Step-by-step explanation:</u>

Yoko: x + 5

Rafael: 3x

Jim: x

Yoko + Rafael + Jim = Total text messages

x + 5 +    3x    +   x   =  100

5x + 5 = 100

5x = 95

x = 19

************

Yoko: x + 5 = (19) + 5   = 24

Rafael: 3x = 3(19) = 57

Jim: x = 19

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ASAP! I will give you branilest
Yuliya22 [10]

Answer:

1.6cm

Step-by-step explanation:

80/50=1.6 cm

Good Luck!

7 0
3 years ago
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In the accompanying diagram of parallelogram ABCD, LaTeX: m\angle A=x+17 m ∠ A = x + 17 and LaTeX: m\angle C=2x-4 m ∠ C = 2 x −
jek_recluse [69]
Answer:
x = 21

Explanation:
In a parallelogram, each two opposite angles are equal.

In the given parallelogram ABCD, we can note that angles A and C are opposite angles. This means that they have equal measures.

Therefore:
∠A = ∠C
x + 17 = 2x - 4
17 + 4 = 2x - x
x = 21

We can check:
angle A = 21 + 17 = 38°
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Hope this helps :)

3 0
3 years ago
How many gallons of water is being filled each minute? (8th Math)
Nadya [2.5K]

Answer:

3 gallons

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4 0
2 years ago
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Solve each equation by factoring.<br> (x – 7)(2x - 3) = 0
Orlov [11]

Answer:

x = 7 and 3/2

Step-by-step explanation:

We can say:

x - 7 = 0 and 2x - 3 = 0

<em>Lets solve for x - 7 = 0 first:</em>

Add 7 to each side of "="

=> <u>x = 7</u>

<em>Now lets solve for 2x - 3 = 0</em>

First add 3 to each side of "="

=> 2x = 3

Now divide each side by 2

<u>=> x = 3/2</u>

Hope this helps!

5 0
2 years ago
A game is played with a spinner on a circle, like the minute hand on a clock. The circle is marked evenly from 0 to 100, so, for
zheka24 [161]

Answer:

The probability is 1/2

Step-by-step explanation:

The time a person is given corresponds to a uniform distribution with values between 0 and 100. The mean of this distribution is 0+100/2 = 50 and the variance is (100-0)²/12 = 833.3.

When we take 100 players we are taking 100 independent samples from this same random variable. The mean sample, lets call it X, has equal mean but the variance is equal to the variance divided by the length of the sample, hence it is 833.3/100 = 8.333.

As a consecuence of the Central Limit Theorem, the mean sample (taken from independant identically distributed random variables) has distribution Normal with parameters μ = 50, σ= 8.333. We take the standarization of X, calling it W, whose distribution is Normal Standard, in other words

W = \frac{X - \mu}{\sigma} = \frac{X - 50}{8.333} \simeq N(0,1)

The values of the cummulative distribution of the Standard Normal distribution, lets denote it \phi , are tabulated and they can be found in the attached file, We want to know when X is above 50, we can solve that by using the standarization

P(X > 50) = P(\frac{X-50}{8.33} > \frac{50-50}{8.33}) = P(W > 0) = \phi(0) = 1/2

Download pdf
8 0
3 years ago
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