Answer:
i dont know if this help but To do this, we will use a 'for loop'. The “for loop” allows the programmer to call a section of code repeatedly within a range of values. The range() function will return integer values depending on the arguments.
Explanation:
Answer:
the array must first be sorted.
Explanation:
Binary search is an efficient algorithm used to find an item from a sorted list of items by using the run-time complexity of Ο(log n), where n is total number of elements.
Binary search applies the principles of divide and conquer.
In order to do a binary search on an array, the array must first be sorted in an ascending order.
Hi!
Our computers will have system software and application software. Application software would be something like a game or just any general purpose app you've downloaded.
Hopefully, this helps! =)
Answer:
import java.util.Scanner;
public class LabProgram {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int inputYear;
boolean isLeapYear;
isLeapYear = false;
inputYear = scnr.nextInt();
// If a year is divisible by 400, then it is a leap year
if (inputYear % 400 == 0)
isLeapYear = true;
// If a year is divisible by 100, then it is not a leap year
if (inputYear % 100 == 0)
isLeapYear = false;
// If a year is divisible by 4, then it is a leap year
if (inputYear % 4 == 0)
isLeapYear = true;
if(isLeapYear)
System.out.println(inputYear + " is a leap year.");
else
System.out.println(inputYear + " is not a leap year.");
}
}
Explanation:
- Take the year as an input from user and store it to inputYear variable.
- If the year is a century year, check if the year is divisible by 400 ( the year must be evenly divisible by 400 ), then set the boolean isLeapYear to true. If a year is divisible by 100, then set the boolean isLeapYear to false. If a year is divisible by 4, then set the boolean isLeapYear to true.
- Check if isLeapYear is true, then print that it is a leap year. Otherwise, print that it is not a leap year.
Output:
1712
1712 is a leap year.
