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Akimi4 [234]
3 years ago
15

What are the advantages and disadvantages of using a very large memory cell size, say, W = 64 instead of the standard size W = 8

? If each integer occupies one 64-bit memory cell and is stored using sign/magnitude notation, what are the largest (in terms of absolute value) positive and negative integers that can be stored? What if two cells are used to store integers?
Computers and Technology
1 answer:
stepladder [879]3 years ago
7 0

Answer and Explanation:

  • The benefits of an large size memory cell is that you can store a lot bigger numbers (and all information is, eventually, numbers) in one cell, which by and large improves the speed and unwavering quality of information get to.  
  • The inconvenience is that you go through a bigger bit of whatever information stockpiling medium you are utilizing on each expression of information, and accordingly can store less information generally speaking.  
  • The biggest positive integer that could be put away in a framework utilizing sign/size documentation, with 64-piece cells is 263. On the off chance that two such cells were utilized to store numbers, the biggest whole number that could be put away by the framework is 2127.
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B - because you should always be honest when it comes to working your hours and getting paid the right amount.
5 0
3 years ago
In a batch operating system, three jobs are submitted for execution. Each job involves an I/O activity, CPU time and another I/O
Ilia_Sergeevich [38]

Answer:

a) CPU utilization for uniprogramming system = 18.2%

b) CPU utilization for multiprogramming system = 41.379%

Explanation:

IO time = total time – CPU time

For JOB 1  

CPU time = 3ms ,

total time= 23ms

IO time = 23-3 = 20ms ,

For JOB 2

CPU time =5ms

total = 29ms

IO time = 29-5 = 24ms  

For JOB 3  

CPU time = 4ms

total = 14ms

IO time = 14-10 =10ms  

1.) In uniprogramming system, operations are performed sequentially

CPU utilization=total CPU time / total real time

CPU utilization =(3+5+4) / (23+29+14)

CPU utilization =0.182 or 18.2%

2) In multiprogramming system, jobs wait for the CPU to get free while performing IO operations concurrently

steps followed by the os

1. IO for 1st job                           at 0ms

2. IO for 2nd job                          at 0ms

3. IO for 3rd job                          at 0ms

4. CPU time for 3rd job              at 5ms

5. Next IO job for 3rd job           at 9ms END at 14ms

6. CPU time for 1st job              at 9ms

7. Next IO job for 1st job           at 14ms END at 23ms

8. CPU time for 2nd job             at 14ms

9. Next IO job for 2nd job          at 15ms END at 29ms

CPU time is 3+5+4 =12ms

Total execution time = 29ms

CPU utilization = 12*100/29= 41.379%

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The goals of _____ are to determine the work load at which systems performance begins to degrade and to identify and eliminate a
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Answer:

volume testing hope this helps :)

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Fiesta28 [93]

Answer:

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7 0
3 years ago
Calculate the shear stress (lbf/in^2) for a given normal stress (lbf/in^2) that is applied to a material with a given cohesion (
LenaWriter [7]

MOHR-COULOMB FAILURE CRITERIA:

In 1900, MOHR-COULOMB states Theory of Rupture in Materials which defines as “A material fails due to because of a critical combination of normal and shear stress, not from maximum normal or shear stress”. Failure Envelope is approached by a linear relationship.

If you can not understand the below symbols see the attachment below

 f   f ()  

Where:      f = Shear Stress on Failure Plane  

       ´= Normal Stress on Failure Plane

 See the graph in the attachment

For calculating the shear stress, when Normal stress, cohesion and angle of internal friction are given. Use this formula:   shear stress =  f  c   tan 

Where,  

• f  is Shear Stress on Failure Plane

• c  is Cohesion

•  is Normal Total Stress on Failure Plane

•  is Friction Angle

8 0
3 years ago
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