Solution:
The flagging of an uncommon last name as a spelling error can be stopped by opening the shortcut menu on the first occurrence of the name and selecting of ignoring all.
Thus the required right answer is B.
<h2>
Answer:</h2>
Option A: Both POP3 and IMAP keep email on an email server by default.
is the correct answer.
<h2>
Explanation:</h2>
Following points will make the idea of POP3 and IMAP clear:
<h3>POP3:</h3>
- POP3 is the acronym for Post Office Protocol 3.
- POP3 is the method of receiving emails in which the emails received on the app can be downloaded on to the computer by having an internet connection.
- These downloaded emails can be viewed offline whenever needed and managed as well.
- POP3 makes it possible that the storage space of the default server do not run short as the downloaded emails are deleted from the server.
<h3>IMAP:</h3>
- IMAP stands for Internet Message Access Protocol.
- It is the method in which the mails are viewed and managed directly on the internet server instead of downloading them on the computer.
- IMAP makes sure to manage the mails so carefully and timely so that unimportant mails are deleted to make sure that the storage space does not run short.
<h3>
Conclusion:</h3>
So from these points we can make sure that both ways keep emails on email server but POP3 have option to download mails from server while IMAP dont have.
<h2>
I hope it will help you!</h2>
Explanation:
A.)
we have two machines M1 and M2
cpi stands for clocks per instruction.
to get cpi for machine 1:
= we multiply frequencies with their corresponding M1 cycles and add everything up
50/100 x 1 = 0.5
20/100 x 2 = 0.4
30/100 x 3 = 0.9
CPI for M1 = 0.5 + 0.4 + 0.9 = 1.8
We find CPI for machine 2
we use the same formula we used for 1 above
50/100 x 2 = 1
20/100 x 3 = 0.6
30/100 x 4 = 1.2
CPI for m2 = 1 + 0.6 + 1.2 = 2.8
B.)
CPU execution time for m1 and m2
this is calculated by using the formula;
I * CPI/clock cycle time
execution time for A:
= I * 1.8/60X10⁶
= I x 30 nsec
execution time b:
I x 2.8/80x10⁶
= I x 35 nsec
Answer:
Comparison.
Explanation:
When we have to find a largest in a list of n elements.First we have to iterate over the list so we can access all the elements of the list in one go.Then to find the largest element in the list we have to initialize a variable outside the loop with the minimum value possible and in the loop compare each element with this value,if the element is greater than the variable assign the element to the variable.Then the loop will find the largest element and it will be the variable.
