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Lerok [7]
2 years ago
11

Write the number shown in standard notation. 1.02 x 10 A. 1,020,000 B. 102,000,000 C. 102,000 D. 10,200,000

Mathematics
2 answers:
vitfil [10]2 years ago
8 0

Your answer should be A please mark brainlest

Irina18 [472]2 years ago
7 0

i think its c

Step-by-step explanation:

don't count me on this

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two trains depart Charlotte at the same time. one train heads North at 60 mph. there other train heads South at 40 mph. after 4
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Answer:

Step-by-step explanation:

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3 years ago
The sum of a number and 6% of itself is 42.4. find the number
kvasek [131]

Answer:

40

Step-by-step explanation:

6% of number = 6/100 × x = 6x/100 = 3x/50

Sum of the number and 6% of itself = 42.4

x + (3x/50) = 42.4

(50x+3x)/50 = 42.4

53x = 42.4 × 50

53x = 2120

x = 2120/53

x = 40


8 0
3 years ago
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There are 318 fiction books in the class library. The number of nonfiction books is 47 less than the number of fiction books. Ho
grigory [225]

Answer:

589 books in total

Step-by-step explanation:

fiction books= 381

non-fiction= 381-47= 271

total amount of books(ficton books and non-fiction books together)= 589 books in total

6 0
3 years ago
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If you wish to warm 40 kg of water by 18 ∘C for your bath, find what the quantity of heat is needed. Express your answer in calo
Harman [31]

Answer:

Quantity of heat needed (Q) = 722.753 × 10³

Step-by-step explanation:

According to question,

Mass of water (m) = 40 kg

Change in temperature ( ΔT) = 18°c

specific heat capacity of water = 4200 j kg^-1 k^-1

The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .

So, Heat (Q) = m×s×ΔT

Or,          Q = 40 kg × 4200 × 18

or,           Q = 3024 × 10³ joule

Hence, Quantity of heat needed (Q) = 3024 × 10³ joule    

In calories 4.184 joule = 1 calorie

So, 3024 × 10³ joule = 722.753 × 10³

6 0
3 years ago
Which of these is a simplified form of the equation 7x + 4 = 5 + 3x + 1x?
Leviafan [203]

Answer:

Step-by-step explanation:

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6 0
3 years ago
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