All categories

3 years ago

State if the two triangles are congruent, if they are state how you know.

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

4 0

Answer:

I belive it would be HL because its defenitly not SSS

Step-by-step explanation:

HL Postulate is if the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg of another right triangle, then the two triangles are congruent.

You might be interested in

Angle RST is a right angle. Angle RSU has a measure of 25°.

Angelina_Jolie [31]

Keywords

complementary angles, right angle

we know that

If two angles are complementary angles, then their sum is equal to a right angle

In this problem

$Angle\ RSU+Angle\ TSU=90\°$ -------> by complementary angles

we have

$Angle\ RSU=25\°$

Substitute and solve for Angle TSU

$Angle\ TSU=90\°-25\°=65\°$

therefore

the answer is the option

$65\°$

5 0

3 years ago

Read 2 more answers

What is the answer for -|-5x(-7)|

Airida [17]

Answer will be -35

Since in an absolute equation, the inside will all be positive. So get rid of the negatives. 5x7. Then, outside of the absolute sign, there is a negative sign. Since that is outside, you cannot turn it into positive. Now, the answer is -35.

7 0

3 years ago

Read 2 more answers

Fast I will give brainlist The total number of seats in a movie theater is calculated by adding the area of the upper section gi

Blizzard [7]

Answer:

(888)

Step-by-step explanation:

okay u stupi if u ont kno jkjk i ont kno byee

5 0

3 years ago

PLSSS HELP IF YOU TURLY KNOW THISS

Novay_Z [31]

Answer:

18225

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A number is selected randomly from the integer from 10to30 what is the probability of picking a multiple of 4or5

arlik [135]

Answer:

$\frac{3}{7}$

Step-by-step explanation:

Start by finding how many integers there are from 10-30...

30-10+1=20+1=21

Note we have to add 1 since it is inclusive.

Now, let's find how many multiples of 4 or 5 there are from 10-30...

4*3=12

4*4=16

4*5=20

4*6=24

4*7=28

5*2=10

5*3=15

5*4=20

5*5=25

5*6=30

5+5-1=9

Note we have to subtract 1 since 20 is counted twice.

The probability would be...

$\frac{Multiples\ of\ four\ and\ five\ from\ 10-30}{Amount\ of\ integers\ between\ 10-30}=\frac{9}{21}=\frac{3}{7}$

6 0

2 years ago