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Karolina [17]
3 years ago
12

The total cost CC (in dollars) to participate in a ski club is given by the literal equation C=85x+60C=85x+60, where xx is the n

umber of ski trips you take
How many ski trips do you take if you spend a total of $315? $485?
Mathematics
2 answers:
vovikov84 [41]3 years ago
7 0

Answer:

The total cost C (in dollars) to participate in a ski club is given by the literal equation :

C=85x+60

Where x is the number of ski trips you take.

1. When C = 315 ;substituting the value of C in the above equation.

315=85x+60

=> 85x=315-60

=> 85x=255

x = 3 trips.

2. When C = 485

485=85x+60

=> 85x=485-60

=> 85x=425

x = 5 trips.

Morgarella [4.7K]3 years ago
6 0
First of all why is there 2 similar equation connected to one another?

Second in order to solve this all you need to do is plug in the number and solve for x

For 485

85x+60=485
85x=420
X=5

Do the same thing and you get 3
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3 years ago
7800 dollars is placed in an account with annual interest rate of 6.5. how much will be in the account after 29 years​
Andru [333]

Answer:

Approx. $48,443.25, if rounding up to the hundredths place.

Step-by-step explanation:

For this problem, use the formula for compound interest:

a = p(1 + r/n)^nt

- P represent the initial amount placed in an account.

- R is the interest rate.

- N is the number of times the interest rate is compounded; If compounded once a year or annually, n would be equal to one.

- T is the amount of time.

So, based on the question, we can fill in some of the formula. "7800 dollars is placed in an account", "annual interest rate of 6.5", and "after 29 years​" tell us what the variables above stand for within this problem.

I then filled in the formula (this is assuming the interest rate is 6.5%) :

a = 7800(1 + .065/1)^29

Now we solve-

1. First, solve within the parenthesis:

a = 7800(1.065^1)^29

2. Solve the exponent outside of the parenthesis:

a = 7800 * 6.21067245356

3. Multiply:

a = 48,443.245137768 or approx. $48,443.25

7 0
4 years ago
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7 0
4 years ago
Read 2 more answers
A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 430 gram setting. It
Zanzabum

Answer: We reject H₀  we find that the machine is underflling the bottles

P ( 421 ± 4,3376 )

Step-by-step explanation:

We assume a normal distribution

Population mean 430 grs

Unknown standard deviation

We have a one tail condition "underfilling"

And our test is:

Null hypothesis      H₀         X  =  μ₀

Alternative hypothesis    Hₐ     X  < μ₀

We must use t student distribution and find the interval

X ± t*(s/√n)

In that expession   X is the sample mean  421 grs, "s"  is sample standard deviation, n is sample size, then

421 ±  t * ( 15 / √21 )          (1)

We go to t table and look for t value for  α = 0,1 and df = 21 - 1   df = 20

we get t (remember it is a one tail test)  t = 1,325, plugging this value in equation (1) we get the interval

421 ± 1,325 * ( 15/√21 )    ⇒  421 ±  1,325 * ( 3,2737)

421 ± 4,3376  

421 + 4,3376  = 425,34

421 - 4,3376  = 416,66

As we can see the mean value of the population 430 grs is not inside the interval  [ 416,66 ;  425,34 ] then we can assure the machine is underfilling the bags, and not meeting the setting spec

6 0
4 years ago
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