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2 years ago

Which of the following is not a real number?

Mathematics

2 answers:

Rudiy272 years ago

7 0

Answer:

Step-by-step explanation:

if you put it in the calculator it says error. I was taught to only use positive numbers. for example √4

Artemon [7]2 years ago

6 0

Answer:

$\sqrt{ - 4}$

Step-by-step explanation:

Non real number are neither irrational numbers(

$\sqrt{3}$

and rational numbers (-2 or 1/2)

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Please help it is due in 10 minutes

Otrada [13]

Answer:

1. X= 4

2. X= 1

3. X= 3

4. X= 5

5. X= 7

6. X= -3/4

7. X= 6

8. X= 5

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

ASAP

rewona [7]

Answer: 90 people

Step-by-step explanation:

3 ladles per person = 150 people x 3

= 450 ladles full

450 ladles full = 5 ladles per one person = 450/5 = 90 people

8 0

3 years ago

Solve 7x 6 < 3(x - 2).{x | x > -3}{x | x < -3}{x | x < -2}{x | x < 0}

Lelechka [254]

7x + 6 < 3(x - 2)
7x + 6 < 3x - 6
7x - 3x < -6 - 6
4x < -12
x < -12/4
x < -3

<span>{x | x < -3}</span>

6 0

3 years ago

I don’t understand how to do this

schepotkina [342]

Answer:

The solution is $x =0.$

Step-by-step explanation:

The equation

$\bold{(1).}\: sin(\dfrac{3\pi }{2} +x)+sin(\dfrac{3\pi }{2} +x) =-2$

can be rewritten as

$2* sin(\dfrac{3\pi }{2} +2) =-2$

and can be further simplified to

$sin(\dfrac{3\pi }{2}+x ) =-1$ .

Now, taking the inverse sine of both sides we get:

$sin^{-1}(sin(\dfrac{3\pi }{2} +x) =sin^{-1}(-1)$

$\bold{(2).}\: \dfrac{3\pi }{2} +2 =sin^{-1}(-1)$

The value of the right side on the interval $[0,2\pi)$ is

$sin^{-1}(-1) = \dfrac{3\pi}{2} \: \:( \text{or }270^o)$ ,

which makes the equation (2)

$\dfrac{3\pi }{2}+x =\dfrac{3\pi}{2}$

solving for $x$ gives

$\boxed{x = 0}$

which is our solution.

4 0

3 years ago

What is the length, width, and area

Temka [501]

Length: 6 Width: 2 Area: 12

4 0

3 years ago