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2 years ago

Which of the following is not a real number?

Mathematics

2 answers:

Rudiy272 years ago

7 0

Answer:

Step-by-step explanation:

if you put it in the calculator it says error. I was taught to only use positive numbers. for example √4

Artemon [7]2 years ago

6 0

Answer:

$\sqrt{ - 4}$

Step-by-step explanation:

Non real number are neither irrational numbers(

$\sqrt{3}$

and rational numbers (-2 or 1/2)

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Please help i don’t understand

olganol [36]

9514 1404 393

Answer:

Step-by-step explanation:

Vertical angles share a vertex point, and have opposite rays for sides. In short, they are across the point of intersection from each other. Vertical angles do not have a common side (they are <em>not</em> adjacent).

The first part of the problem is to identify angle NCA. That is shown in red in the attachment. The vertical angle is across the point of intersection. It is angle 3.

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3 years ago

Use a known maclaurin series to obtain the maclaurin series for the given function. f(x = 8x2 tan?1(7x3

11Alexandr11 [23.1K]

Going out on a limb here and guessing that the function is

$f(x)=8x^2\tan^{-1}(7x^3)$

Please correct me if this isn't the case.

Recall that

$\tan^{-1}x=\displaystyle\sum_{n\ge0}\frac{(-1)^nx^{2n+1}}{2n+1}$

which converges for $|x|$ .

It follows that

$8x^2\tan^{-1}(7x^3)=8x^2\displaystyle\sum_{n\ge0}\frac{(-1)^n(7x^3)^{2n+1}}{2n+1}$
$=\displaystyle\sum_{n\ge0}\frac{56(-49)^nx^{6n+3}}{2n+1}$

6 0

3 years ago

Consider M, N, and P. collinear points on MP.

Kobotan [32]

Answer:

See explanation

Step-by-step explanation:

There are three possible cases:

1. Point N lies between M and P, then MN + NP = MP. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{NP}-\dfrac{MN}{MN+NP}=\dfrac{MN(MN+NP)-MN\cdot NP}{NP(MN+NP)}=\\ \\=\dfrac{MN^2+MN\cdot NP-MN\cdot NP}{NP(MN+NP)}=\dfrac{MN^2}{NP(MN+NP)}$

2. Point N lies to the right from point P, then MP + PN = MN. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MP+PN}{NP}-\dfrac{MP+PN}{MP}=\dfrac{MP}{NP}+1-1-\dfrac{NP}{MP}=\dfrac{MP^2-NP^2}{NP\cdot MP}$

3. Point N lies to the left from point M, then NM + MP = NP. Consider needed difference:

$\dfrac{MN}{NP}-\dfrac{MN}{MP}=\dfrac{MN}{MN+MP}-\dfrac{MN}{MP}=\dfrac{MN\cdot MP-MN(MN+MP)}{MP(MN+MP)}=\\ \\=\dfrac{MN\cdot MP-MN^2-MN\cdot MP}{MP(MN+MP)}=\dfrac{-MN^2}{MP(MN+MP)}$

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2 years ago

Need help with the following question

andrew11 [14]

3 times. Draw a line 1 unit up, and you can see that there are 3 intersections.

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2 years ago

Turkey tastes like napkins

vesna_86 [32]

So you ate napkins before? And some turkey is dry lol

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3 years ago