X=length
y=width
Area (rectangle)=length x width
we suggest this system of equations:
y=x/5
xy=9/20
solve this system of equations by substitution method:
x(x/5)=9/20
x²/5=9/20
Least common multiple=20
4x²=9
x²=9/4
x=⁺₋√(9/4)
we have two solutions:
x₁=-3/2 it does not validate
x₂=3/2 ⇒y=x/5=(3/2)/5=3/10
The dimensions of the lake are:
lengh=3/2 miles
width=3/10 miles
to check:
Area=3/2 miles x 3/10 miles=9/20 miles².
width is 1/5 the length of the lake ⇒ 3/10 miles=(3/2) /5 miles
Answer:
The radius 10 cm
Step-by-step explanation:
∵ The volume of the cone = 1/3 πr²h
∵ v = 1256 cm³
∵ h = 12 cm
∴ 1256 = 1/3 π (12) r²
∴ r² = 1256 × 3/12π = 100 cm
∴ r = √100 = 10 cm
Answer: b = 8
Step-by-step explanation:
Use the Pythagorean theorem
A square + B square = C square
C square - A square = B square
C square - B square = A square
10 - 6 = b --Square it
100 - 36 = 64 (square root)
64 = 8
b = 8 miles
Answer:
G) Yes, because the plots and the linear model both align to produce a similar calculated sum.
H) I need to see the data table again for step 2d.
Step-by-step explanation:
1.) You scatter plot should be off by 6.97, since that was the first difference in your data table set of terms.
Basically subtract all of the GPAs from the Hours in the table.
Ex). Hours - GPA = Difference
or like before,
9.2 - 2.23 = 6.97
Do the rest of the numbers like this then plot the answers. I'd advise you plot your second set of scatter plot points in a different color.
Answer:
Step-by-step explanation:
An ellipse is the locus of a point such that its distances from two fixed points, called foci, have a sum that is equal to a positive constant.
The equation of an ellipse with a center at the origin and the x axis as the minor axis is given by:
Since the distance of the satellite from the surface of the moon varies from 357 km to 710 km, hence:
b = 357 km + 959 km = 1316 km
a = 710 km + 959 km = 1669 km
Therefore the equation of the ellipse is:
