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Korvikt [17]
2 years ago
13

T + (-5) = 14 can someone solve the equation please?

Mathematics
2 answers:
mezya [45]2 years ago
5 0
Answer: t = 19

Expiation: you add 5 on each side
Alja [10]2 years ago
4 0

Answer: 19

Add 5 to both sides

t - 5 = 14

t - 5 + 5 =14 + 5

Simplify

T=19

Hope this helped

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Use the arc length formula to find the length of the curve y = 4x − 5, −1 ≤ x ≤ 2. check your answer by noting that the curve is
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3 years ago
Least common multiple of 168 and 76
yuradex [85]

Answer:

Best to draw out a factor tree.

4 0
3 years ago
Read 2 more answers
Solve 5/7x=-25<br> The solution is x= ?
Bad White [126]
The answer To this is x=-35
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3 years ago
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Step-by-step explanation:

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13^4 x 13^7= (13^4)^7, false

13^(4+7) = 13^11

(13^4)^7 = 13^(4×7) = 13^28

y^5 x y^0/y^3=(y^2)^1 , true

y^5 x y^0/y^3 = y^(5+0-3) = y^2

(y^2)^1 = y^(2×1) = y^2

q^0 x q^5/q^2=(q^3)^2/q^3, true

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6 0
3 years ago
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Jenny and Natalie are selling cheesecakes for a school fundraiser. Customers can buy chocolate cakes and vanilla cakes. Jenny so
IrinaVladis [17]

The cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

<em><u>Solution:</u></em>

Let "c" be the cost of 1 chocolate cake

Let "v" be the cost of 1 vanilla cake

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Therefore, we can frame a equation as:

14 x cost of 1 chocolate cake + 5 x cost of 1 vanilla cake = 119

14 \times c + 5 \times v=119

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<em><u>Natalie sold 10 chocolate cakes and 10 vanilla cakes for 130 dollars</u></em>

Therefore, we can frame a equation as:

10 x cost of 1 chocolate cake + 10 x cost of 1 vanilla cake = 130

10 \times c + 10 \times v = 130

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<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 2

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<em><u>Subtract eqn 2 from eqn 3</u></em>

28c + 10v = 238

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( - ) --------------------------

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c = 6

<em><u>Substitute c = 6 in eqn 1</u></em>

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84 + 5v = 119

5v = 119 - 84

5v = 35

v = 7

Thus cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

8 0
3 years ago
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