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Sveta_85 [38]
3 years ago
8

Find two consecutive even integers whose some is 66

Mathematics
2 answers:
Mars2501 [29]3 years ago
6 0

Answer:

32 & 34

Step-by-step explanation:

Let's solve your equation step-by-step.

x+x+2=66

Step 1: Simplify both sides of the equation.

x+x+2=66

(x+x)+(2)=66(Combine Like Terms)

2x+2=66

2x+2=66

Step 2: Subtract 2 from both sides.

2x+2−2=66−2

2x=64

Step 3: Divide both sides by 2.

2x/2=64/2

x=32

32 +2 = 34

marusya05 [52]3 years ago
4 0
2 consecutive even integers....x and x + 2

x + x + 2 = 66
2x + 2 = 66
2x = 66 - 2
2x = 64
x = 64/2
x = 32

x + 2 = 32 + 2 = 34

ur 2 integers are : 32 and 34
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Kitty [74]

Answer:

5) A

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Step-by-step explanation:

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A local kids play sold 8 adult tickets and 9 child tickets for a total of $205. On day two they sold only 4 adult tickets and 3
Naya [18.7K]

Answer:

The price of 1 adult ticket is $ 11 and price of 1 child ticket is $13

Step-by-step explanation:

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Cost of 3 child tickets = 3y

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Plot 1 and 2 on graph

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4x+3y=83  -- Blue line

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Then, Cross multiply, multiplying the numerator/top number of the second fraction/ratio, by the denominator/bottom number in the first fraction/ratio.

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