Answer:
area of triangle= 1/2*h*b
= 1/2*6*16
=3*16
= 48 yd²
This is your answer. If I'm right so,
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The answer is 5. Measure r and t are congruent. Measure r is 20 so measure t is also 20. So by dividing 20 by 4 you get 5.
Answer:
5) A
6) A
Step-by-step explanation:
5) With the sides of the rectangle being dilated, multiply the side lengths by the scale factor
7.5(2.2) and 3(2.2)
16.5 and 6.6
6) Multiply the coordinates by the scale factor as dilations work as (x, y) -> (kx, ky)
Answer:
The price of 1 adult ticket is $ 11 and price of 1 child ticket is $13
Step-by-step explanation:
Let x be the cost of 1 adult ticket
Let y be the cost of 1 child ticket
Cost of 8 adult tickets = 8x
Cost of 9 child tickets = 9y
We are given that A local kids play sold 8 adult tickets and 9 child tickets for a total of $205
So, 8x+9y=205 ----- 1
Cost of 4 adult tickets = 4x
Cost of 3 child tickets = 3y
We are given that 4 adult tickets and 3 child tickets for a total of $83.
4x+3y=83 ----2
Plot 1 and 2 on graph
8x+9y=205 -- Red line
4x+3y=83 -- Blue line
Intersection point provides the solution
So, Intersection point =(11,13)
So, The price of 1 adult ticket is $ 11 and price of 1 child ticket is $13
Set up a proportion to describe this relationship. So, for every 2 cats, there is five dogs. Therefore, “c” can represent your unknown quantity for every 35 animals.
2/5 = c/35
Cross multiply, multiplying the numerator/top number of the first fraction/ratio, by the denominator/bottom number in the second fraction/ratio.
2 • 35 = 70
Then, Cross multiply, multiplying the numerator/top number of the second fraction/ratio, by the denominator/bottom number in the first fraction/ratio.
C • 5 = 5c
So, now the problem shows both products as equal to each other.
70 = 5c
To solve for the variable, “c”, you must isolate the variable, by performing the opposite/inverse operation of multiplication, since that will undo the multiplication, for the variable to stand alone. Therefore, divide both sides of the equation by 5.
70/5 = 5c/5
14 = c
So, there is 14 cats out of 35 animals.