Find two consecutive even integers whose some is 66

Mathematics

2 answers:

Mars2501 [29]3 years ago

6 0

Answer:

32 & 34

Step-by-step explanation:

Let's solve your equation step-by-step.

x+x+2=66

Step 1: Simplify both sides of the equation.

x+x+2=66

(x+x)+(2)=66(Combine Like Terms)

2x+2=66

Step 2: Subtract 2 from both sides.

2x+2−2=66−2

2x=64

Step 3: Divide both sides by 2.

2x/2=64/2

x=32

32 +2 = 34

marusya05 [52]3 years ago

4 0

2 consecutive even integers....x and x + 2

x + x + 2 = 66
2x + 2 = 66
2x = 66 - 2
2x = 64
x = 64/2
x = 32

x + 2 = 32 + 2 = 34

ur 2 integers are : 32 and 34

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In parallelogram DEFG if m_DEF=110° find m_FGD. E 110° D G

Sergio039 [100]

Answer:

E=x

or 110= x ( opposite angles of parallelogram are congurent)

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110+D =180

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Answer:

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Step-by-step explanation:

$\left(\dfrac{1}{x}+x\right)^2=25\qquad\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\\left(\dfrac{1}{x}\right)^2+2(x\!\!\!\!\diagup)\left(\dfrac{1}{x\!\!\!\!\diagup}\right)+x^2=25\\\\\dfrac{1}{x^2}+2+x^2=25\qquad\text{subtract 2 from both sides}\\\\\dfrac{1}{x^2}+x^2=23$