Question

11. Find the equation for the circle with center ​(−2​,4​) and passing through ​(5​,−3​).

Answer 1

Answer:

In standard form: (x+2)² + (y-4)² = 98

Use the distance formula to find radius:

$\sf d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}$

where (x1, y1), (x2, y1) are points

$\rightarrow \sf d = \sqrt{(-2 - 5)^2 + (4-(-3))^2}$

$\rightarrow \sf d = \sqrt{(-7)^2 + (7)^2}$

$\rightarrow \sf d = 7\sqrt{2}$

Equation of circle:

• (x-h)² + (y-k)² = r²

• (x-(-2))² + (y-4)² = (7√2)²

• (x+2)² + (y-4)² = (7√2)²

• (x+2)² + (y-4)² =  98

Answer 2

(-2,4) I’m not that good at math pls tell me if I’m wrong