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3 years ago

Can someone help me with this

Mathematics

1 answer:

Vikentia [17]3 years ago

7 0

<1 and <7 measures 42 degrees
2 and 5 are alternate interior angles from the figure above

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An elevator starts at floor 5.It goes up 6 floors twice, and then it goes down 8 floors. A second elevator

Gre4nikov [31]

Answer:

Answer is The 2nd elevator

Step-by-step explanation:

1st Elevator

5+12 = 17

17- 8 = 9

so 1st elevator ends on floor 9th

2nd Elevator

21-10 = 11

11+9 = 20

2nd Elevator ends on floor 20th

so therefore the elevator that ends on the higher floor is the 2nd elevator

4 0

3 years ago

Help! I’ll mark brainliest

OleMash [197]

Answer:

answer is the second one

8 0

3 years ago

Graph the linear equation and answer each of the following questions. y=-2x-3 (A)What is the y-intercept?

balandron [24]

A) The Y-intercept of this equation is 3

B) The slope of this equation is 2

C) This equation has a positive slope

D) Starting from the Y-intercept, I simply went over to the right 1 box, and up 2 boxes

I hope this helps!

5 0

3 years ago

1.Find by factors the square root of 3600<br>2. Find by factors the cube root of 343

Contact [7]

Answer:

1)60

2)7

Step-by-step explanation:

1)The square root of 3600 is 60. It is the positive solution of the equation x2 = 3600. The number 3600 is a perfect square.

2)The cube root of 343 is the number which when multiplied by itself three times gives the product as 343. Since 343 can be expressed as 7 × 7 × 7. Therefore, the cube root of 343 = ∛(7 × 7 × 7) = 7.

4 0

3 years ago

Read 2 more answers

Help!!!!!!!!!!!!!!!!

kaheart [24]

Answer:

$\cos\alpha\sin\alpha(\cos\alpha-\sin\alpha)$

Step-by-step explanation:

First, simplify each term:

$\sin\left(\dfrac{\pi}{2}+\alpha\right)=\cos \alpha\\ \\\cos \left(\dfrac{\pi}{2}+\alpha\right)=-\sin \alpha\\ \\\cos \left(\alpha-\dfrac{3\pi}{2}\right)=-\sin \alpha\\ \\\sin \left(\dfrac{3\pi}{2}+\alpha\right)=-\cos \alpha$

Then given expression is equivalent to

$\cos ^3\alpha+(-\sin \alpha)^3-(-\sin \alpha)+(-\cos \alpha)\\ \\=\cos ^3\alpha-\sin^3 \alpha+\sin \alpha-\cos \alpha\\ \\=(\cos\alpha-\sin\alpha)(\cos^2\alpha+\cos\alpha\sin\alpha+\sin^2\alpha)-(\cos\alpha-\sin\alpha)\\ \\=(\cos\alpha-\sin\alpha)(1+\cos\alpha\sin\alpha-1)\ \ [\cos^2\alpha+\sin^2\alpha=1]\\ \\=\cos\alpha\sin\alpha(\cos\alpha-\sin\alpha)$

6 0

3 years ago