Well if you have 60 and she has 120 i will set it out as a sequence week by week 60,67,74,81,88,95,102,109,116,123,130,137,144,151,158,165,172,179,186,193,200,207,214,221,228,235,242,249,256,263,270 120,125,130,135,140,145,150,155,160,165,170,175,180,185,190,195,200,205,210,215,220,225,230,235,240, 245,250,255,260,265,270 it would take 31 weeks and the total is 270
We have 8 dozen bagels, or 8*12=96 bagels. Each plate can hold 14 bagels, so we have enough bagels to fill 96/14=about 6.86 plates. However, we cannot have a fraction of a plate, so we round up to have a total of seven plates. To fill all seven plates fully, 7*14=98 bagels would be needed, which is two more than we have.
To summarize, Mr. Corsetti has seven plates of bagels, and would need two more bagels to fill the last one up.
First you want to figure out what exactly it is you are looking for. We are looking for "capital letters that have rotational symmetry but do not have line symmetry"
So: 1. Must have rotational symmetry. This means that if we rotate the capital letter 180 deg, either clockwise or counterclockwise, it will still look the same
2. Must not have line symmetry. If an object has line symmetry, it means that if you draw a line down the middle (in any way), it will be symmetrical on both sides. We need capital letters that do not fit that condition.
Now we look at all capital letters. We find that H, I, N,O, S, X, and Z are all rotationally symmetrical. Think about it. If you rotate them, they still look the same.
But, we have to make sure they do not have line symmetry. If we draw a line right down the middle of H, I, O and X (**note, the have multiple lines of symmetry), they are symmetrical on both sides of the line.
