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yanalaym [24]
1 year ago
15

What weight (in grams) of h2so4 would be needed to make 750.0 ml of 2.00 m solution?

Chemistry
1 answer:
frosja888 [35]1 year ago
8 0

Answer:

I think the answer should be 147

Explanation:

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The movement of one or more from one reactant to another is called
mrs_skeptik [129]

Answer: Redox Reaction

Explanation:

Redox reaction is the key chemical events in an oxidation-reduction also called Redox. It is the net movement of electrons from one reactants to another

7 0
3 years ago
Crystals are characterized by particular patterns that repeat in how many dimensions? A. three dimensions
Andreyy89

A option is correct answer   .

8 0
3 years ago
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Which process created the gases of earth’s first atmosphere?
lisov135 [29]

Answer:

Volcanic Activity

Explanation:

3 0
3 years ago
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In a certain electrolysis experiment, 1.24 g of Ag were deposited in one cell (containing an aqueous AgNO3 solution), while 0.65
eduard

Answer:

The correct answer is 169.56 g/mol.

Explanation:

Based on the given information, the mass of Ag deposited is 1.24 g, and the mass of unknown metal X deposited in another cell is 0.650 g. The number of moles of electrons can be determined as,

= 1.24 g Ag * 1mol Ag/107.87 g/mol Ag * 1 mol electron/1 mol Ag ( the molecular mass of Ag is 107.87 g/mol)

= 0.0115 mole of electron

The half cell reaction for the metal X is,  

X^3+ (aq) + 3e- = X (s)

From the reaction, it came out that 3 faraday will reduce one mole of X^3+.  

The molar mass of X will be,  

= 0.650 g/0.0115 *3 mol electron/1 mol

= 56.52 * 3

= 169.56 g/mol

7 0
3 years ago
Acetylene, c2h2, has a standard enthalpy of formation, δh° = 226.7 kj/mol, and a standard entropy change for its formation from
VLD [36.1K]
ΔG⁰ = ΔH⁰ - T ΔS⁰

ΔG⁰ : Standard free energy of formation of acetylene

ΔH⁰ : Standard enthalpy of formation (226.7 kJ/mol)

ΔS⁰ : Standard entropy change (58.8 J / K. mol)

T : Temperature 25°C = 298 K (room temperature)

ΔG⁰ = 226.7 - (298 x 58.8 x 10⁻³) = 209.2 kJ /mol
5 0
2 years ago
Read 2 more answers
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