I'm not sure how many sign fig's you are required to have.
However I think the final answer would be 0.05 Moles, because of the .5g, that is considered 1 sign fig.
The balanced equation for the reaction between Mg and O₂ is as follows
2Mg + O₂ --> 2MgO
stoichiometry between Mg and O₂ is 2:1
number of Mg reacted - 4.00 mol
if 2 mol of Mg reacts with 1 mol of O₂
then 4.00 mol of Mg requires - 1/2 x 4.00 = 2.00 mol of O₂
then the mass of O₂ required - 2.00 mol x 32.0 g/mol = 64.0 g
64.0 g of O₂ is required for the reaction
Ni(OH)₂(s) ⇄ Ni²⁺(aq) + 2OH⁻(aq)
Ksp=2.0*10⁻¹⁵
Ksp=[Ni²⁺][OH⁻]²
c=[Ni²⁺]=[OH⁻]/2
Ksp=c×(2c)²=4c³
c=∛(Ksp/4)
c=∛(2.0×10⁻¹⁵/4)=0.01995 mol/L ≈ 0.02 mol/l
Answer:
You can't choose a very long question as refer to our Brainly rules. This question is too long. Next time make it simple.
Explanation:
First one one Dihydroxyacetone
