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yanalaym [24]
2 years ago
15

What weight (in grams) of h2so4 would be needed to make 750.0 ml of 2.00 m solution?

Chemistry
1 answer:
frosja888 [35]2 years ago
8 0

Answer:

I think the answer should be 147

Explanation:

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what would be the final volume when 2.20 M solution is made from 25.0 mL of a 12.0 M solution? plzz show work
cupoosta [38]

Answer:

136.36 mL

Explanation:

Here we have to use the dilution formula

From C1V1= C2V2

Where;

C1= initial concentration of the solution= 12.0 M

C2= final concentration of the solution= 2.20 M

V1 = initial volume of the solution= 25.0 ml

V2= final volume of the solution= ?????

Then recall;

C1V1=C2V2

V2 = C1V1/C2

Substituting values from the parameters given;

V2= 12.0 × 25.0 / 2.20

V2= 136.36 mL

7 0
3 years ago
Coke is an impure form of carbon that is often used in the in- dustrial production of metals from their oxides. If a sample of c
steposvetlana [31]

Answer:

The mass of coke needed to react completely with 1.0 ton of copper(II) oxide is 0.794 Ton.

Explanation:

2CuO+C\rightarrow 2Cu+CO_2

1 Ton = 907185 grams

Mass of copper oxide = 1.0 Ton = 907185 grams

Moles of copper oxide =\frac{907185 g}{79.55 g/mol}=11,403.95 moles

According to reaction, 2 moles of copper oxide reacts with 1 mole of carbon.

Then 11403.95 moles of copper oxide will react with:

\frac{1}{2}\times 11403.95 mol=5,701.98 mol of carbon

Mass of 5,701.98 moles of carbon:

5,701.98 mol\times 12 g/mol=68,423.75 g

Mass of coke = x

Mass of carbon = 68,423.75 g

Percentage of carbon in coke = 95%

95\%=\frac{68,423.75 g}{x}\times 100

x=720,250.09 g=0.794 Ton

The mass of coke needed to react completely with 1.0 ton of copper(II) oxide is 0.794 Ton.

3 0
3 years ago
Help me 20 points please someone just get this done
faust18 [17]

Answer:

whut done

Explanation:

I ain't see nothing

6 0
3 years ago
Read 2 more answers
A mixture was found to contain 1.05 g if silicone dioxide, 0.69 g cellulose, 1.82 g of calium carbonate. what percent of calcium
djverab [1.8K]
1,05+ 0,69 + 1,82 = 3,56g of mixture

%CaCO₃: 1,82/3,56×100% = 0,5112×100% = 51,12%
5 0
3 years ago
Anyone think they can help me with this one?
BARSIC [14]
To name this Alkyne, simply count from the direction that will give the lowest starting number to appear at the beginning of the carbon triple bond.

If you were to count from the top of the chain, the position of the carbon next to the triple bond would be 4. Yet if you count from the bottom chain going left to right and above the chain, the position of the carbon next to the triple bond would be 3.

Then identify the groups that are connected off the parent chain, here we have a methyl group on carbon 2.

Thus the name would be 2 - methyl - 3 - heptyne. I believe.
4 0
3 years ago
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