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Vesna [10]
3 years ago
9

As of December 31, 2020 $ 13,000. As of December 31, 2021 $ 25,000The enacted tax rate was 25% for 2020 and thereafter.What shou

ld be the balance in Kent's deferred tax liability account as of December 31, 2021?
Mathematics
1 answer:
blondinia [14]3 years ago
8 0

Answer:

$3,000

Step-by-step explanation:

The computation of the balance in Kent deferred tax liability is shown below:        

= {(December 31 2021) × (enacted tax rate)} - {(December 31 2020) × (Enacted tax rate)}

= {($25,000 × 25%) - ($13,000 × 25%)}

= $6,250 - $3,250

= $3,000

Along with the journal entry is also shown for better understanding

Income tax expense $41,500

       To Deferred tax liability $3,000

       To Income tax payable $38,250    ($153,000 × 25%)

(Being the income tax expense is recorded)

We debited the income tax expense as it increases the expenses account and on other side we credited the other two accounts as these are also increased

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The total cost as $96

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To find the total amount find the tax amount and the tip amount

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A quadtratic equation that has x intercepts of -8,0 and 2,0 and has a vertical stretch of 3
Paladinen [302]

Answer:

f(x) = 3(x + 8)(x - 2)

Step-by-step explanation:

The intercept form of a quadratic function is y = a(x - r)(x - s), where r and s are the x-intercepts and a is the vertical stretch/compression factor.

If the intercepts are at (-8, 0) and (2, 0), and the vertical stretch is 3, just substitute these values into the intercept form formula, and you're done!

Please mark as Brainliest! :)

7 0
3 years ago
F:[1/2,infinity)—&gt;[3/4,infinity) <br> f(x)=x^2-x+1 <br> find the inverse of f(x);please explain
dexar [7]

Answer:

f^{-1}(x)=\frac{1}{2}+\sqrt{x-\frac{3}{4}}

Step-by-step explanation:

y=x^2-x+1

We want to solve for x.

I'm going to use completing the square.

Subtract 1 on both sides:

y-1=x^2-x

Add (-1/2)^2 on both sides:

y-1+(-1/2)^2=x^2-x+(-1/2)^2

This allows me to write the right hand side as a square.

y-1+1/4=(x-1/2)^2

y-3/4=(x-1/2)^2

Now remember we are solving for x so now we square root both sides:

\pm \sqrt{y-3/4}=x-1/2

The problem said the domain was 1/2 to infinity and the range was 3/4 to infinity.

This is only the right side of the parabola because of the domain restriction. We want x-1/2 to be positive.

That is we want:

\sqrt{y-3/4}=x-1/2

Add 1/2 on both sides:

1/2+\sqrt{y-3/4}=x

The last step is to switch x and y:

1/2+\sqrt{x-3/4}=y

y=1/2+\sqrt{x-3/4}

f^{-1}(x)=1/2+\sqrt{x-3/4}

8 0
3 years ago
If sin(x) = cos(y) for acute angles x and y, how are the angles related?
Vesnalui [34]

Answer:

b. complementary

Step-by-step explanation:

-Complementary angles are angles that add up to 90°.

-These are usually the two acute angles in the right triangle.

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Cos \ 60\textdegree=0.5\\\\Sin \ 30\textdegree=0.5\\\\\therefore Sin \ 30\textdegree=Cos \ 60 \textdegree=0.5

#We can reverse as:

Sin \ 60\textdegree=0.86603\\\\Cos \ 30\textdegree=0.86603\\\\\therefore Sin \ 60\textdegree=Cos \ 30\textdegree=0.86603

Hence, two angles are said to be complimentary if they sum up to 90°.

6 0
3 years ago
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