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Natalka [10]
2 years ago
12

What do you call a line segment which passes throughthe center of the circle from on side to the other?​

Mathematics
2 answers:
alukav5142 [94]2 years ago
5 0

Answer:

diameter of the circle

Step-by-step explanation:

A chord that passes through a circle's centre is a diameter of the circle.

tatiyna2 years ago
3 0

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Please help me I’ll give you 100 points
Nat2105 [25]

Answer and Step-by-step explanation:

So, you would do 100 times 31.8, which is 3180, that'll be the area of the rectangle.

Now, the semicircles. They together form a circle.

So, we do pi times d (diameter), which is 3.14 times 31.8 = 99.852

Now we add them together.

99.852 + 3180 = 3279.85 (rounded to the nearest hundredth of a meter)

The rectangle area is 3180.

The Semi circles' combined area is 99.85.

<u>The total area of the figure is 3279.85.</u>

<em><u></u></em>

<em><u>I hope this helps! Have a great day!</u></em>

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<em><u>#teamtrees #PAW (Plant And Water)</u></em>

7 0
3 years ago
Read 2 more answers
Help please?????????????????
son4ous [18]
This is Pythagorean theorem. 
We already know a and c. 
a = 4 and c = 10
4² + b² = 10² 
16 + b² = 100 
Subtact 16 from each side. 
b² = 84 
Square root of each side: 
b = ≈9.165 or √84

Hope this helps!
6 0
3 years ago
I need help finding the answer for this.​
Dmitry [639]
The Answer is 12 meters.
7 0
3 years ago
Help I need you right nowwwwwwwwwwww
earnstyle [38]

Answer:

6/8

just add the fractions together after making the bottom the same

4 0
3 years ago
Read 2 more answers
The cost of six hens and one duck at the university poultry farm is GH₵40. While four hens and three ducks cost GH₵36. What is t
Anon25 [30]

Answer:

Step-by-step explanation:

Let's call hens h and ducks d. The first algebraic equation says that 6 hens (6h) plus (+) 1 duck (1d) cost (=) 40.

The second algebraic equations says that 4 hens (4h) plus (+) 3 ducks (3d) cost (=) 36.

The system is

6h + 1d = 40

4h + 3d = 36

The best way to go about this is to solve it by substitution since we have a 1d in the first equation. We will solve that equation for d since that makes the most sense algebraically. Doing that,

1d = 40 - 6h.

Now that we know what d equals, we can sub it into the second equation where we see a d. In order,

4h + 3d = 36 becomes

4h + 3(40 - 6h) = 36 and then simplify. By substituting into the second equation we eliminated one of the variables. You can only have 1 unknown in a single equation, and now we do!

4h + 120 - 18h = 36 and

-14h = -84 so

h = 6.

That means that each hen costs $6. Since the cost of a duck is found in the bold print equation above, we will sub in a 6 for h to solve for d:

1d = 40 - 6(6) and

d = 40 - 36 so

d = 4.

That means that each duck costs $4.

3 0
3 years ago
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