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Rainbow [258]
2 years ago
13

What is the simplified form of this expression (-3x^2+4x)+(2x^2-x-11)

Mathematics
2 answers:
uysha [10]2 years ago
8 0

<u>Given expression:</u>

(-3x^2+4x)+(2x^2-x-11)

To simplify the expression, it is needed to open the parentheses.

\implies (-3x^2+4x)+(2x^2-x-11)

\implies -3x^2+4x+2x^2-x-11

To further simplify the expression, let us combine like terms.

\implies -3x^2+4x+2x^2-x-11

\implies x^{2} (-3 + 2)+x(4-1)-11

Now, simplify the expression as needed.

\implies x^{2} (-3 + 2)+x(4-1)-11

\implies x^{2} (-1)+x(3)-11

Finally, open the parentheses to get the simplified form

\implies x^{2} (-1)+x(3)-11

\implies \boxed{\bold{-x^{2} +3x-11}}

\text{Therefore, the simplified expression is} \ \boxed{-x^{2} +3x-11}

zlopas [31]2 years ago
5 0

Answer:

SolutioN :

\bf \: \star ( - 3x^{2}  + 4x) + (2 {x}^{2}  - x - 11)

\longrightarrow \bf \:  - 3 {x}^{2}  + 4x + 2 {x}^{2}  - x - 11

\longrightarrow \bf \:  - 3 {x}^{2}  + 2 {x}^{2}  + 4x - x - 11

\longrightarrow  \boxed{\bf \:  - {x}^{2}  + 3x - 11}

-------------HappY Learning <3 ----------

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Answer:

Please check the explanation.

Step-by-step explanation:

a)  How much will you have at the middle of the first year?

Principle P = $300

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Compound n = Semi-Annually = 2

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Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

substituting the values

A=300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(0.5\right)}

A=300\cdot \frac{2.06}{2}

A=\frac{618}{2}

A=309 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 0.5 years is $ 309.00.

Part b) How much at the end of one year?

Principle P = $300

Annual rate r = 6% = 0.06 per year

Compound n = Semi-Annually = 2

Time (t in years) = 1 years

Total amount = A = ?

Using the formula

A\:=\:P\left(1+\frac{r}{n}\right)^{nt}

so substituting the values

A\:=\:300\left(1+\frac{0.06}{2}\right)^{\left(2\right)\left(1\right)}

A=300\cdot \frac{2.06^2}{2^2}

A=318.27 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 300.00 at a rate of 6% per year  compounded 2 times per year  over 1 year is $ 318.27.

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Step-by-step explanation:

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