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2 years ago

5√5-2√5 can someone please simplify this before I throw my phone across the floor thankyou

Mathematics

1 answer:

Eddi Din [679]2 years ago

5 0

Answer:

3 sqrt 5 ( or 6.7082039 as posted in earlier A )

Step-by-step explanation:

sqrt ( 5) ( 5-2) = 3sqrt 5

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What is the range for y=x^2-7x-8 ?

gtnhenbr [62]

Answer:

[-20.25;+∞).

Step-by-step explanation:

1) according to the properties of the given parabola the minimum is:

$x_0=-\frac{-7}{2}=3.5; \ y_0=-20.25;$

2) y₀=-20.25 means, the value -20.25 is minimum of the range, the maximum →+∞;

3) finally, the range y≥-20.25.

7 0

1 year ago

*WILL MARK BRANLIEST PLEASE ANSWER* Guys what is the perimeter? -PHOTO INCLUDED-

Black_prince [1.1K]

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Perimeter of a triangle = sum of measures of each side ;

$\qquad \rightarrow \sf p = 9 \: ft + 8y + 14 \: ft$

$\qquad \rightarrow \sf p =23 \: ft + 8y$

3 0

2 years ago

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Consider a circle that has a circumference of 28/3.14 centimeters. What is the area of this circle? Answer fast plz also can you

bija089 [108]

Answer:

$A=6.33\ cm^2$

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The circumference of a circle is equal to

$C=2\pi r$

we have

$C=\frac{28}{3.14}\ cm$

$\pi=3.14$

substitute the values

$\frac{28}{3.14}=2(3.14)r$

$r=\frac{28}{19.7192}\ cm$

$r=1.42\ cm$

step 2

Find the area of the circle

The area of the circle is equal to

$A=\pi r^{2}$

substitute the values

$A=(3.14)(1.42)^{2}$

$A=6.33\ cm^2$

7 0

3 years ago

A 4 metre ladder is placed against a vertical wall.

Black_prince [1.1K]

Answer:

Original position: base is 1.5 meters away from the wall and the vertical distance from the top end to the ground let it be y and length of the ladder be L.

Step-by-step explanation:

By pythagorean theorem, L^2=y^2+(1.5)^2=y^2+2.25 Eq1.

Final position: base is 2 meters away, and the vertical distance from top end to the ground is y - 0.25 because it falls down the wall 0.25 meters and length of the ladder is also L.

By pythagorean theorem, L^2=(y -0.25)^2+(2)^2=y^2–0.5y+ 0.0625+4=y^2–0.5y+4.0625 Eq 2.

Equating both Eq 1 and Eq 2: y^2+2.25=y^2–0.5y+4.0625

y^2-y^2+0.5y+2.25–4.0625=0

0.5y- 1.8125=0

0.5y=1.8125

y=1.8125/0.5= 3.625

Using Eq 1: L^2=(3.625)^2+2.25=15.390625, L=(15.390625)^1/2= 3.92 meters length of ladder

Using Eq 2: L^2=(3.625)^2–0.5(3.625)+4.0625

L^2=13.140625–0.90625+4.0615=15.390625

L= (15.390625)^1/2= 3.92 meters length of ladder

hope it helps...

correct me if I'm wrong...

4 0

2 years ago

PLEASE HELP!!!!!!!!! ASAP!!!!! I REWARD BRAINLIEST!!!! HAVE CLASS IN 30 MINUTES!1111

KiRa [710]

Answer:

$y = \dfrac{1}{3}x + 1$

Step-by-step explanation:

The given line is in slope-intercept form,

y = mx + b,

where m is the slope.

The slope of the given line is 1/3, so m = 1/3.

Parallel lines have equal slopes, so the slope of the parallel line is also 1/3.

y = 1/3 x + b

Now we can find the equation of the parallel line through point (6, 3) by using the given point's coordinates for x and y and solving for b.

3 = (1/3)(6) + b

3 = 2 + b

b = 1

Equation: $y = \dfrac{1}{3}x + 1$

8 0

2 years ago

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