A complex number usually took the form a+bi where a and b are real numbers and 'i' represents an imaginary number. For a quadratic equation, the complex roots for the root of a quadratic equation took the form known as complex conjugates. The complex conjugates are formed by changing the sign of the imaginary part.

SO, if a quadratic equation has 4-i as a solution, the other solution must be 4+i.

6 0

2 years ago

35 POINTS. I need help! Please!

topjm [15]

There is no solution for the first one

if you eliminate y you get 2 equations
-13x - 13z = -25
-13x - 13x = -15

- there is no solution to theses

a23 means the element in the second row and the 3rd column

so its -5

7 0

3 years ago

Line AB has endpoints A(-4,5) and B(3,5). What is the x-coordinate of a point C such that B is the midpoint of line AC

Ipatiy [6.2K]

Easy peasy

the midpoint between $(x_1,y_1)$ and $(x_2,y_2)$ is
$(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$
just average them

so given that (3,5) is the midpoint of (-4,5) and (x,y)
$(\frac{-4+x}{2},\frac{5+y}{2})=(3,5)$
so by logic
$\frac{-4+x}{2}=3$ and $\frac{5+y}{2}=5$
times both sides by 2 for everybody
-4+x=6 and 5+y=10
add 4 to both sides for left one and minus 5 from both sides for right
x=10 and y=5

the coordinate of point C is (10,5)
the x coordinate is 10

7 0

3 years ago