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2 years ago

HELPP FOR BRAAINLISTT

Mathematics

2 answers:

Phoenix [80]2 years ago

5 0

Answer:

The slope is approximately 2 and the y-intercept is approximately 3.

Step-by-step explanation:

I don't know if this is right but I hope it is have an amazing day.

viva [34]2 years ago

5 0

B is the correct answer. Hope this helps!

You might be interested in

The variables y and x have a proportional relationship. When y = 10, x = 8 What is the value of x when y = 14? Enter your answer

ivanzaharov [21]

X=11.2

10. 14
—- = ———
8. X

10x= 112
————-
10. 10

X=11.2

3 0

3 years ago

The number of vehicles passing through a bank drive -up line during each 15-minute period was recorded. The results are shown be

tangare [24]

Answer:

Step-by-step explanation:

I think the median you are asking is the middle value,

because there is a total of 20 vehicles, there are two middle number: 31 and 31.

To solve this:

you first plus these two numbers together, you will get 62.

then divide them by 2, then you will get the middle number.

the middle number will be 31. ( actually because theese two number are the same, you do not really need to plus them then divide by 2, you could just answer the question 31, but because when you do other question and has the same situation but not the same number, (suppose you got 20 and 21) Then you need to do this question like I said above)

I wish this could help you.

8 0

3 years ago

Plz hurry!!!!!!! How do you find it?

Colt1911 [192]

Answer:

hope you can see it

the law of cosine is

c2 =a2+b2-2abcos(c)

7 0

3 years ago

The concentration of hexane (a common solvent) was measured in units of micrograms per liter for a simple random sample of sixte

goldenfox [79]

Answer:

Yes, it can be concluded that the mean hexane concentration is less in treated water than in unsaturated water

Step-by-step explanation:

The number of of specimen in the samples of untreated water, n₁ = 16

The sample mean, $\overline x_1$ = 228.0

The sample standard deviation, s₁ = 4.3

The number of of specimen in the samples of treated water, n₂ = 20

The sample mean, $\overline x_2$ = 224.6

The sample standard deviation, s₂ = 5.0

The level of significance = 0.10

The null hypothesis, H₀; $\overline x_1$ ≥ $\overline x_2$

The alternative hypothesis, Hₐ; $\overline x_1$ < $\overline x_2$

The degrees of freedom = 16 - 1 = 15

The test statistic, $t_{\alpha}$ = 1.341

$t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}-\dfrac{s _{2}^{2}}{n_{2}}}}$

Plugging in the values, we get;

$t=\dfrac{(224.6- 228.0)}{\sqrt{\dfrac{5.0^{2}}{20} -\dfrac{4.3^{2} }{16}}} \approx -11.0675$

Given that the t-value is large, the corresponding p-value is low, therefore, we fail to reject the null hypothesis and there is considerable statistical evidence to suggest that the mean hexane concentration is less in treated than in untreated water, therefore, we have; $\overline x_1$ ≥ $\overline x_2$

6 0

3 years ago

Explain how to use partial quotients to divide 235 by 5

katrin [286]

Eso nos da igual a 47

4 0

3 years ago