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3 years ago

Write a quadratic function in standard form with zeros 5 and 6

Mathematics

1 answer:

N76 [4]3 years ago

6 0

Answer:

${x}^{2} - 11x +30$

Step-by-step explanation:

Zeros = 5 & 6

Let the variable of the quadratic function be x

Therefore, (x - 5) & (x-6) are factors

$(x - 5)(x - 6) \\ \\ = {x}^{2} - (5 + 6)x + ( - 5)( - 6) \\ \\ = {x}^{2} - 11x +30 \\ is \: the \: required \: quadratic \: \\function.$

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hi, I got assigned stupid khan academy as homework and if I don’t get 900 points I’m screwed. Can anybody help please?

Roman55 [17]

Answer:

A.)z+y+x

Step-by-step explanation:

Addition (+) is a commutative operator.

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3 years ago

The cost of coffee is determined by the type of coffee beans that are mixed together. The cost of a local mix of Arabica and Rob

Andreyy89

Answer:

If a mixture contains 1000 pounds of Arabica beans, there should be <u>250 pounds of Robusta beans</u> in the mixture.

Step-by-step explanation:

700A+1,200R=1,000,000

700(1000) +1,200R=1,000,000 - First, plug in the A value and simplify .

700000+1,200R=1,000,000 - Then, subtract 700,000 from both sides.

1,200R=300,000 - Finally, divide by 1,200 on both sides of the equation.

R=250 - This is your value for R, or the Robusta beans.

<u>250 pounds of Robusta beans</u>

Hope this helps!

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3 years ago

The length of the sides of the base of the largest of the Great Pyramids of Giza, near Cairo, Egypt, is 230 m. This square pyram

Lorico [155]

For this case we have that the volume of the square pyramid is given by:
V = ((L ^ 2) * (h)) / 3
Where,
L: side of the base
h: height
Substituting values we have:
V = ((230 ^ 2) * (147)) / 3
V = 2592100 m ^ 3
Answer:
the volume of the pyramid is:
V = 2592100 m ^ 3

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3 years ago

400 meters to 350 meters

OleMash [197]

Minus 150 meters pepega I don’t quite understand the question but that is one way to get from 400 to 350 meters.

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3 years ago

What is the range of the following function:<br> y = 2(5^x) - 1

Orlov [11]

<h2>Hello!</h2>

The answer is:

The range of the function is:

Range: y>2

Range: (2,∞+)

To calculate the range of the following function (exponential function) we need to perform the following steps:

First: Find the value of "x"

So, finding "x" we have:

$y=2(5^{x}-1)\\\frac{y}{2}=5^{x}-1\\\\\frac{y}{2}-1=5^{x}\\\\Log_{5}(\frac{y}{2}-1)=Log_5(5^{x})\\\\x=Log_{5}(\frac{y}{2}-1)$

Second: Interpret the restriction of the function:

Since we are working with logarithms, we know that the only restriction that we found is that the logarithmic functions exist only from 0 to the possitive infinite without considering the number 1.

So, we can see that if the variable "x" is a real number, "y" must be greater than 2 because if it's equal to 2 the expression inside the logarithm will tend to 0, and since the logarithm of 0 does not exist in the real numbers, the variable "x" would not be equal to a real number.

Hence, the range of the function is:

Range: y>2

Range: (2,∞+)

Note: I have attached a picture (the graph of the function) for better understanding.

Have a nice day!

5 0

3 years ago