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Ahat [919]
3 years ago
7

Diameter of a cone base is 5 cm and a slant height is 4M find surface area

Mathematics
1 answer:
Nutka1998 [239]3 years ago
4 0

Hi there!

The total surface area (tsa) of a cone can be calculated with this formula :

TSA = (\pi × r × slant height) + \pi × r²


The "r" stands for "radius". The radius is equal to half the diameter, so in order to be able to use the formula, you'll need to divide the diameter by 2 to find the radius :

5 ÷ 2 = 2.5 = radius


Since the slang height is in meters, you'll need to transform it into centimeters in order to have both values in centimeters. To do so you'll need to use the cross product method :

1 m = 100 cm

4 m = x cm

(100 × 4) ÷ 1 = x cm

400 ÷ 1 = x cm

400 = x cm → The slant height is 400cm.


Now replace all the information in the formula and calculate everything :

TSA = (\pi × 2.5 × 400) + (\pi × 2.5²)

TSA = (\pi × 1,000) + (\pi × 6.25)

TSA ≅ 3,141.59 + 19.63

TSA ≅ 3,161.22 cm²


There you go! I really hope this helped, if there's anything just let me know! :)

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Step-by-step explanation:

Tan is Opposite by Adjacent. the opposite side is 16, adjacent side is 12 and hypotenuse is 20.

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0.077

Step-by-step explanation:

From the table :

Number of students aged 31 - 35 = 60

Number of students over 35 = 26

Total number of students = total possible outcomes = 1123

Required outcome = (students aged 31 - 35) + over 35 = 60 + 26 = 86

Probability = required outcome / Total possible outcomes

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What is the<br> area of the<br> parallelograrn?<br> 16 in<br> in 2<br> 13 in
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A researcher collects data on the number of times race horses are raced during their careers. The veterinarian finds that the av
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95% confidence for µ, the average number of times a horse races

(12.493 , 18.107)

Step-by-step explanation:

<u>Explanation</u>:-

The veterinarian finds that the average number of races a horse enters is 15.3

The mean of the sample x⁻ = 15.3

Given standard deviation of the sample 'S' = 6.8

Given sample size 'n' = 25

Degrees of freedom = n-1 =25-1 =24

The tabulated value 't' = 2.064 at two tailed test 0.95 level of significance

<u> 95% confidence for µ, the average number of times a horse races</u>

<u></u>(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } , x^{-} +  t_{\alpha }\frac{S}{\sqrt{n} } )<u></u>

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(12.493 , 18.107)

<u>Conclusion</u>:-

95% confidence for µ, the average number of times a horse races

(12.493 , 18.107)

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